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3 years ago

What is the quotient of (x^3+3x^2-4x-12) divided by (x^2+5x+6)

Mathematics

1 answer:

makvit [3.9K]3 years ago

5 0

Answer:

x - 2

Step-by-step explanation:

x^3 + 3x^2 - 4x - 12 simplifies to (x + 2)(x - 2)(x + 3)

x^2 + 5x + 6 simplifies to (x + 2)(x + 3)

(x + 2)(x - 2)(x + 3)

(x + 2)(x + 3)

The (x + 2) and (x + 3) cancel

x - 2

Kayden Kohl

9th Grade Student

(Algebra 2)

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3 years ago

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IgorLugansk [536]

Answer:

Step-by-step explanation:

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3 years ago

If tan theta= 3/4 , find csc theta

dangina [55]

Answer:

$csc\theta=\frac{5}{3}$

Step-by-step explanation:

Given:

$tan\theta =\frac{3}{4}$

$cot\theta =\frac{4}{3}$ [∵ $cot\theta =\frac{1}{tan\theta}$ ]

Squaring both sides.

$cot^2\theta =\frac{4^2}{3^2}=\frac{16}{9}$

$csc^2\theta -1=\frac{16}{9}$ [∵ $cot^2\theta =csc^2\theta-1]$ ]

Adding 1 to both sides.

$csc^2\theta -1+1=\frac{16}{9}+1$

$csc^2\theta =\frac{16}{9}+1$

$csc^2\theta=\frac{16}{9} +\frac{9}{9}$ [Taking LCD=9 and adding fractions ]

$csc^2\theta=\frac{16+9}{9}$

$csc^2\theta=\frac{25}{9}$

Taking square root both sides.

$\sqrt{csc^2\theta}=\sqrt{\frac{25}{9}}$

∴ $csc\theta=\frac{5}{3}$

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3 years ago

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Dominik [7]

Answer:

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