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3 years ago

Evaluate the expression for the given values of the variables.

Mathematics

1 answer:

Dahasolnce [82]3 years ago

4 0

4(2m-n)-3(2m-n)

4(2(-15)- -18)-3(2(-15)- -18)
4(-30- -18)-3(-30- -18)
4(-12) -3(-12)
-48- -36
-12

The answer is C

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A local animal feed company makes its feed buy a ton which is 2000 pounds. They want to include a medication in the field. Each

r-ruslan [8.4K]

Answer: There is 400 grams of medication that should the feed company ad for each ton of food they produce.

Step-by-step explanation:

Since we have given that

Quantity of medication each country need a day = 300 mg

Number of pounds per day consumes by each cow = 15 pounds

So, it becomes

$\dfrac{300}{15}=20\ mg/pounds$

As we know that

1 g = 1000 mg

So, 20 mg = $\dfrac{20}{1000}=0.02\ g/pounds$

Total number of pounds = 2000 pounds

So, number of grams of medication that should the feed company ad for each ton of food they produce is given by

$2000\times 0.02=400\ grams/ton$

Hence, there is 400 grams of medication that should the feed company ad for each ton of food they produce.

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3 years ago

Which table represents a proportional relationship that has a constant of proportionality equal to 0.8?

garri49 [273]

Answer:

correct answer is B

Step-by-step explanation:

5 0

3 years ago

Round 3.047 to the nearest hundredth

navik [9.2K]

3.05, but if you need sig figs, you should check that

6 0

2 years ago

Drag the tiles to the correct boxes to complete the pairs.

Mashcka [7]

Answer:

Part 1) $-17\frac{8}{9}$ -----> $-6\frac{4}{9}-3\frac{2}{9}-8\frac{2}{9}$

Part 2) $-15.11$ ------> $-12.48-(-2.99)-5.62$

Part 3) $-19\frac{8}{9}$ -----> $-19\frac{2}{9}-4\frac{1}{9}-(-3\frac{4}{9})$

Part 4) $-201.65$ -----> $-353.92-(-283.56)-131.29$

Part 5) $74$ ------> $83\frac{1}{5}-108\frac{2}{5}-(-99\frac{1}{5})$

Step-by-step explanation:

Part 1) we have

$-6\frac{4}{9}-3\frac{2}{9}-8\frac{2}{9}$

To calculate the subtraction convert the mixed numbers to an improper fractions

$6\frac{4}{9}=\frac{6*9+4}{9}=\frac{58}{9}$

$3\frac{2}{9}=\frac{3*9+2}{9}=\frac{29}{9}$

$8\frac{2}{9}=\frac{8*9+2}{9}=\frac{74}{9}$

substitute

$-\frac{58}{9}-\frac{29}{9}-\frac{74}{9}=-\frac{(58+29+74)}{9}=-\frac{161}{9}$

Convert to mixed number

$-\frac{161}{9}=-(\frac{153}{9}+\frac{8}{9})=-17\frac{8}{9}$

Part 2) we have

$-12.48-(-2.99)-5.62$

To calculate the subtraction eliminate the parenthesis first

$-12.48-(-2.99)-5.62=-12.48+2.99-5.62=-15.11$

Part 3) we have

$-19\frac{2}{9}-4\frac{1}{9}-(-3\frac{4}{9})$

To calculate the subtraction convert the mixed numbers to an improper fractions

$19\frac{2}{9}=\frac{19*9+2}{9}=\frac{173}{9}$

$4\frac{1}{9}=\frac{4*9+1}{9}=\frac{37}{9}$

$3\frac{4}{9}=\frac{3*9+4}{9}=\frac{31}{9}$

substitute

$-\frac{173}{9}-\frac{37}{9}-(-\frac{31}{9})$

Eliminate the parenthesis

$-\frac{173}{9}-\frac{37}{9}+\frac{31}{9}=\frac{(-173-37+31)}{9}=-\frac{179}{9}$

Convert to mixed number

$-\frac{179}{9}=-(\frac{171}{9}+\frac{8}{9})=-19\frac{8}{9}$

Part 4) we have

$-353.92-(-283.56)-131.29$

To calculate the subtraction eliminate the parenthesis first

$-353.92+283.56-131.29=-201.65$

Part 5) we have

$83\frac{1}{5}-108\frac{2}{5}-(-99\frac{1}{5})$

To calculate the subtraction convert the mixed numbers to an improper fractions

$83\frac{1}{5}=\frac{83*5+1}{5}=\frac{416}{5}$

$108\frac{2}{5}=\frac{108*5+2}{5}=\frac{542}{5}$

$99\frac{1}{5}=\frac{99*5+1}{5}=\frac{496}{5}$

substitute

$\frac{416}{5}-\frac{542}{5}-(-\frac{496}{5})$

Eliminate the parenthesis

$\frac{416}{5}-\frac{542}{5}+\frac{496}{5}=\frac{(416-542+496)}{5}=\frac{370}{5}=74$

3 0

3 years ago

There is a total of 100 calories in 15 of Mei's favorite crackers. What is

borishaifa [10]

Answer:

2,100

Step-by-step explanation:

first you want divide 140 by 20 to find the the amount of calories per cracker so 140 divided by 20 is 7 then all you need to do is multiply 7 time the 300 crackers to get you total of 2,100.

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Hope it helps! 0.0

6 0

3 years ago

Read 2 more answers