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Katen [24]
2 years ago
9

When dividing it’s total debt by total equity what’s a company trying to measure

Computers and Technology
1 answer:
Bond [772]2 years ago
3 0

Answer:

A business's debt-to-equity ratio, or D/E ratio, is a measure of the extent to which a company can cover its debt. It is calculated by dividing a company's total debt by its total shareholders' equity. The higher the D/E ratio, the more difficult it may be for the business to cover all of its liabilities.

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Technology can cause a drop in input costs.<br> a. True<br> b. False
Marizza181 [45]
<span>True that technology can cause a drop in input cost. In a production process, there are three kinds of cost that called input cost, which are the direct material cost, direct labor cost, and overhead cost. Technology usage can make the production process more efficient by reducing labors included in the process. This condition leads to a cost reduction.</span>
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3 years ago
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What tab should you choose if you want to practice presenting with your PowerPoint slides?
dezoksy [38]

Answer:

i think its slideshow tab

Explanation:

tell me if im right

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At a local marketing firm, Steve is the lead Web developer and is responsible for working with customers on their Web designs, d
attashe74 [19]

Answer:

All of the above.

Explanation:

Understanding that he must create a unique domain name for each client

Being able to work with HTML

Understanding of the World Wide Web and how hyperlinks work

All of these would be a critical skill Steve must have to be able to perform his job.

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3 years ago
Which of these sedimentary rocks is made of the largest particles?
Marta_Voda [28]
Your answer is <span>A.conglomerate.

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6 0
3 years ago
Write a program FindDuplicate.java that reads n integer arguments from the command line into an integer array of length n, where
kozerog [31]

Answer:

  1. public class FindDuplicate{
  2.    public static void main(String[] args) {
  3.        Scanner input = new Scanner(System.in);
  4.        int n = 5;
  5.        int arr[] = new int[n];
  6.        for(int i=0; i < arr.length; i++){
  7.            int inputNum = input.nextInt();
  8.            if(inputNum >=1 && inputNum <=n) {
  9.                arr[i] = inputNum;
  10.            }
  11.        }
  12.        for(int j =0; j < arr.length; j++){
  13.            for(int k = 0; k < arr.length; k++){
  14.                if(j == k){
  15.                    continue;
  16.                }else{
  17.                    if(arr[j] == arr[k]){
  18.                        System.out.println("True");
  19.                        return;
  20.                    }
  21.                }
  22.            }
  23.        }
  24.        System.out.println("False");
  25.    }
  26. }

Explanation:

Firstly, create a Scanner object to get user input (Line 4).

Next, create an array with n-size (Line 7) and then create a for-loop to get user repeatedly enter an integer and assign the input value to the array (Line 9 - 14).

Next, create a double layer for-loop to check the each element in the array against the other elements to see if there is any duplication detected and display "True" (Line 21 - 22). If duplication is found the program will display True and terminate the whole program using return (Line 23). The condition set in Line 18 is to ensure the comparison is not between the same element.

If all the elements in the array are unique the if block (Line 21 - 23) won't run and it will proceed to Line 28 to display message "False".

7 0
3 years ago
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