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Anvisha [2.4K]
1 year ago
7

R,u,t,s are positive RXS=15 SXT=3 TXV=7 RXV=??

Mathematics
1 answer:
SSSSS [86.1K]1 year ago
4 0

Answer:

35

Step-by-step explanation:

R × S = 15 could be 5 × 3 = 15, 3 × 5 = 15

                               15 × 1 = 15, 1 × 15 = 15

S ×T =3 From our previous step we can see that S could be 1 or 3 or 5 or 15.

            Given that S×T =3, will make sense that S is 1 or 3

            If S is 1 then T is 3 and if S is 3 then T is 1, so multiplied will give 3.

T×V=7 From previous step we see that T could be 1 or 3.

           Since T×V = 7 it will make sense that T is 1, and therefore V is 7.

T ×V = 7,  S ×T =3, R × S = 15, R × V = ??

1 × 7 = 7,  S ×1 = 3, R × 3 = 15, 5 × 7 = ??

               3 ×1 = 3,  5 × 3 = 15, 5 × 7 = 35

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Step-by-step explanation:

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2[(6x)(6x)]+4[(12x - 9)(6x)]\\=2[36x^2]+4[(12x*6x)-(9*6x)]\\=72x^2+4[72x^2-54x]\\=72x^2+288x^2-216x\\=360x^2-216x

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Step-by-step explanation:

The quadrilateral ABCD consists of two triangles. By adding the area of the two triangles, we get the area of the entire quadrilateral.

Vertices A, B, and C form a right triangle with legs AB=3, BC=4, and AC=5. The two legs, 3 and 4, represent the triangle's height and base, respectively.

The area of a triangle with base b and height h is given by A=\frac{1}{2}bh. Therefore, the area of this right triangle is:

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The other triangle is a bit trickier. Triangle \triangle ADC is an isosceles triangles with sides 5, 5, and 4. To find its area, we can use Heron's Formula, given by:

A=\sqrt{s(s-a)(s-b)(s-c)}, where a, b, and c are three sides of the triangle and s is the semi-perimeter (s=\frac{a+b+c}{2}).

The semi-perimeter, s, is:

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Thus, the area of the quadrilateral is:

6\:\mathrm{cm^2}+2\sqrt{21}\:\mathrm{cm^2}=\boxed{6+2\sqrt{21}\:\mathrm{cm^2}}

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3 years ago
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