Ask question

Ask question

All categories

1 year ago

11

A rocket is launched from a height of 3m with an initial velocity of 15 m/s at what time will the rocket be 13m from the ground?

first person to answer gets brainliest

1 answer:

dem82 [27]1 year ago

4 0

Not sure of my answer but, velocity=delta d/delta t. t=delta d/ velocity
—> t=(13-3)/15=>10/15=2/3s

You might be interested in

Do the table and the equation represent the<br> same function?<br> y = 390 + 11(x)

Aneli [31]

Answer:

NO

Step-by-step explanation:

Try to replace x by -50
y= 390 + 11*(-50) = -160
in the table we have -210 so the table doesn't represent the equation

5 0

2 years ago

Elza [17]

Answer:

$(b)\ 2x - 9 = -1$

$(c)\ -2x + 12 = 4$

$(e)\ 2(x - 10) = -12$

Step-by-step explanation:

Required

Which equals $x = 4$

$(a)\ 2x + 6 = 2$

Collect like terms

$2x = 2 - 6$

$2x = -4$

Divide both sides by 2

$x = -2$

$(b)\ 2x - 9 = -1$

Collect like terms

$2x = -1 + 9$

$2x = 8$

Divide both sides by 2

$x = 4$

$(c)\ -2x + 12 = 4$

Collect like terms

$-2x =- 12 + 4$

$-2x =-8$

Divide both sides by -2

$x = 4$

$(d)\ 2(x + 2) = 10$

Divide both sides by 2

$x + 2 =5$

Collect like terms

$x = 5-2$

$x = 3$

$(e)\ 2(x - 10) = -12$

Divide both sides by 2

$x - 10 = -6$

Collect like terms

$x = 10 - 6$

$x = 4$

Hence, the equations with the required solution are:

$(b)\ 2x - 9 = -1$

$(c)\ -2x + 12 = 4$

$(e)\ 2(x - 10) = -12$

3 0

2 years ago

which of the following represents the equation of the line with an x- intercept of 6 that passes through the point (4,4)?

luda_lava [24]

Answer:

$y=-2x+12$

Step-by-step explanation:

To write the equation of a line, find the slope between two points. Substitute two points into the slope formula. If the equation has an x-intercept of 6 then the line passes through the point (6,0). Use (6,0) and (4,4) in the formula.

$m = \frac{y_2-y_1}{x_2-x_1} =\frac{4-0}{4-6} =\frac{4}{-2} =-2$

Since m = -2, substitute its value and the point (6,0) into the point slope form. Then simplify.

$y-y_1 = m(x-x_1)\\y-0 = -2 (x-6)\\y=-2x+12$

7 0

3 years ago

If a quadrilateral has exactly 2 lines of symmetry and both are angle bisectors then which statement would be true

Bumek [7]

If a quadrilateral has exactly 2 lines of symmetry and both are angle bisectors then the figure must be a rhombus because it has exactly 2 pairs of congruent angles.

I hope this helps! :)

3 0

3 years ago

Read 2 more answers

Find the missing exponent. 2^{3}\cdot 2^{?}=2^{10}2

guapka [62]

Answer:

7

Step-by-step explanation:

2^3 • 2^7 = 2^10

When multiplying exponents, the exponents add up together. In other words, just subtract 10-3 = 7 that would be your missing exponent!

Hope this helps, good luck!

5 0

2 years ago

Read 2 more answers