Answer:
6/11
Step-by-step explanation:
there are 12 gold clips out of 22, so 12/22 and divide both sides by two to simplify.
Sure. If the numerator monomial isn't a multiple of the denominator monomial, you'll end up with a fraction.
Answer:
<em>50 Chef's salads and 50 Caesar salads should be prepared in order to maximize profit.</em>
Step-by-step explanation:
Suppose, the number of Chef's salad is
and the number of Caesar salad is 
On a typical weekday, it sells between 40 and 60 Chefs salads and between 35 and 50 Caesar salads.
So, the two constraints are:
and 
The total number sold has never exceed 100 salads. So, another constraint will be: 
According to the graph of the constraints, the vertices of the common shaded region are:
and
<em>(Refer to the attached image for the graph)</em>
The lunch stand makes a $.75 profit on each Chef's salad and $1.20 profit on each Caesar salad. So, the profit function will be: 
For (40, 35) , 
For (60, 35) , 
For (60, 40) , 
For (50, 50) ,
<u><em>(Maximum)</em></u>
For (40, 50) , 
Profit will be maximum when
and 
Thus, 50 Chef's salads and 50 Caesar salads should be prepared in order to maximize profit.
In the given diagram, the value of the dashed side of rhombus OABC is 5
<h3>Distance between two points </h3>
From the question, we are to determine the length of the dashed line (OA), in rhombus OABC
In the diagram, we can observe that the length of OA is the distance between point A and the origin (O).
Using the formula for calculating distance between two points,
d =√[(x₂-x₁)² + (y₂-y₁)²]
In the diagram,
The coordinate of the origin is (0, 0)
The coordinate of point A is (3, 4)
Thus,
x₁ = 0
x₂ = 3
y₁ = 0
y₂ = 4
Putting the parameters into the formula, we get
OA =√[(3-0)² + (4-0)²]
OA =√(3² + 4²)
OA =√(9+16)
∴ OA =√25
OA = 5
Hence, in the given diagram, the value of the dashed side of rhombus OABC is 5
Learn more on Distance between two points here: brainly.com/question/24778489
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Answer:
10/14, 15/21
Step-by-step explanation:
WE are given a ratio 5/7
To find equivalent ratios it is sufficient to multiply both numerator and denominator by the same number
Let us take 2,3 for example.
When we multiply both numerator and denominator by 2, value does not change.
Hence we get equivalent fraction.
So 10/14 is one such fraction.
Next is multiply by 3
15/21 is another fraction.