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yaroslaw [1]
1 year ago
14

The finances of a group of pet owners were analyzed to determine how much they were spending on their pets each year. Would (3,7

.2) be a viable solution for the function
Mathematics
1 answer:
brilliants [131]1 year ago
6 0

A variable solution for the function is not realistic to have 4.5 owners.

In the given graph x-axis represents the number of owners and the y-axis represents the yearly cost of pets, in hundreds.

It is given that the graph passes through the points (1,15), (3,7), and (10,0).

We need to check whether (4.5, 6) is a realistic solution for the function or not. (4.5,6) point represents

<h3>What is a realistic solution?</h3>

1 showing awareness and acceptance of reality. 2 practical or pragmatic rather than ideal or moral. 3 (of a book, film, etc.) depicting or emphasizing what is real and actual rather than abstract or ideal.

Number of owners = 4.5

the yearly cost of pets = 6

It is realistic that owners spend $600 a year on their pet(s).

A number of owners can not be a fraction value. So, it is not realistic to have 4.5 owners.

Therefore, the correct option is D.

To learn more about the realistic solution visit:

brainly.com/question/7784687

#SPJ1

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This is a warmup for your first project. The drug valium is eliminated from the bloodstream through a decay process with a half-
frosja888 [35]

Step-by-step explanation:

a. We have v as the amount of drug(mg) in the blood at time t (hrs)

b. Flow rate in = k litre/he

For a circulatory system we have the flow rate in and flow rate out to be the same

Therefore,

Flow rate out = k litre/hr

concentration of drug going in = 0mg/litre

Concentration of drug going out = v mg/litre

V(0) = 20mg since 20mg was taken at midnight

V(0) = 20

Half life t1/2 = 36 hours

V(36) = v(0)/2

= 20/2

= 10mg

C. ivp = \frac{dv}{dt}= -kv

v(0) = 20mg\\v(36) = 10mg

d. solution

\frac{dv}{dt}  = -kt\\ln(v) = ln(c) - kt

\frac{v}{c} = e^{-kt}  = v=ce^{-kt}

v(0) = 20

ce^{-k(0)} =20

c = 20

so

v(t) = 20e^{-kt}

e.

t\frac{1}{2}=36hours\\ v(36)= 10

10 = 20e^{-36k}

\frac{1}{2} =e^{-36k}

we take log

k=\frac{ln(2)}{36}

please check attachment for answer f

8 0
3 years ago
How do you solve this?
Rus_ich [418]

Answer:

x=25°, y=10°

Step-by-step explanation:

∠A+∠B=180°

8y+10y=180°

18y=180°

y=10°

∠B+∠C=180°

10y+4x-20°=180°

10*10°+4x=180°+20° (y=10°)

100°+4x=200°

4x=200°-100°

4x=100°

x=25°

4 0
3 years ago
What is 1.83 repeating as a fraction?
maks197457 [2]
The answer to this question would be: 1 5/6

To change a decimal number into fraction, you need to divide the number on the right of decimal point with 1. In this case, the number is 0.83.
This number is hard since .83 doesn't have many factors. To find the answer you can try to multiply the decimal with some number until it close to 1(no decimal left)
0.83* 2= 1.66
0.83* 3= 2.49 ---> close to half, if you find this number, you can try to double it
0.83* 4= 3.32
0.83* 5= 4.15
0.83* 6= 4.98---> close to 1, that means there is high probability that the number can be divided by 6 
0.83 would be 4.98/6, but if we assume that the number is 0.8333...... then 0.83 would be 5/6. So, 1.83 would be 1 5/6
4 0
3 years ago
Read 2 more answers
How you solve this ?
jonny [76]
You have to use Pythagorean theorem

12^2+20^2 = x^2

sqrt(144*400) = x^2
sqrt(544) = x

X = 4  sqrt(34)

3 0
3 years ago
2
Dvinal [7]

Answer:

Help me with this please

7 0
2 years ago
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