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tamaranim1 [39]
3 years ago
10

It is 7 kilometers from kerrys house to the mall. About what is that distance in miles?

Mathematics
1 answer:
GenaCL600 [577]3 years ago
3 0

Answer:

\huge\boxed{\approx 4.4 \  \text{miles}}

Step-by-step explanation:

In order to convert kilometers to miles, we can use a formula, assuming m is miles and k is kilometers.

m = \frac{k}{1.609}.

Since we know the kilometer reading (7), we can divide this by 1.609 to get our total miles.

7 \div 1.609 \approx 4.4

Hope this helped!

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Lola dice Argos mi perro tiene 10 kg menos que roco cuantos kilogramos tiene argos
Elena L [17]

Answer:

A=R-10

Step-by-step explanation:

The problem is:

<em>Lola says: Argos, my dog, has 10 kilograms less than Roco. How much kilograms Argos has?</em>

<em />

This problem is about algebraic language. We just need to express the ordinaty language into an equation.

We know the words less means difference. So, let's call A Argos' weight and R Roco's weight. We can expresse the given problem as

A=R-10

Notice that we applied a difference due to the word "less" in the problem.

Therefore, Argo's weight is given by the expression

A=R-10

7 0
3 years ago
X^2+y^2-4y-15=6
myrzilka [38]

Answer:

x^2 + y^2 - 4y - 15 = 6

x^2 + y^2 - 4y = 21

x^2 + y^2 - 4y + 4 = 25

x^2 + (y - 2)^2 = 5^2

r = 5

8 0
3 years ago
Which equation best describes the relationship between Marla's total pay , p and the number of hours she works , h?
goldfiish [28.3K]

Answer:

d

Step-by-step explanation:

7 0
3 years ago
Determine if the card below represents a reflection over the x-axis or a
gtnhenbr [62]

Answer:

Reflection over y-axis

Step-by-step explanation:

We know that with a reflection of the x-axis, we flip the value of the y value

But since the y-values in Q3 and Q4 are both negative, we know that can't be the case

So it has to be a reflection over the y-axis where the x-values are flipped

Hope this helps

7 0
3 years ago
Solving multi step equations
hichkok12 [17]

The no-brain way to do it is to

  1. subtract one side from both sides so you have <em>(something) = 0</em>.
  2. divide by the coefficient of the variable.
  3. add the opposite of the constant.

Of course, at some point, you need to simplify the equation so you have something like

... ax + b = 0 . . . . . . where <em>a</em> and <em>b</em> are some constants that may be positive or negative

17) Subtract the right side.

... 10(x +3) -(-9x -4) -(x -5 +3) = 0

... 10x + 30 +9x +4 -x +5 -3 = 0 . . . . . eliminate parentheses

... x(10+9-1) +(30+4+5-3) = 0 . . . . . . . collect terms

... 18x +36 = 0 . . . . . . . . . . . . . . . . . . . simplified

... x + 2 = 0 . . . . . . . . . . . . . . . . . . . . . .divide by 18, the coefficient of x

... x = -2 . . . . . . . . . . . . . . . . . . . . . . . . add the opposite of the constant

19) Add the opposite of the left side.

... 0 = -9(1 +7x) +12(x -12)

... 0 = -9 -63x +12x -144 . . . . . . eliminate parenthses

... 0 = -51x -153 . . . . . . . . . . . . . simplify

... 0 = x +3 . . . . . . . . . . . . . . . . . divide by -51, the coefficient of x

... -3 = x . . . . . . . . . . . . . . . . . . . add the opposite of the constant

_____

If you examine the variable's coefficients you can make a choice of side to subtract that results in a positive coefficient of the variable.

This method puts variable and constant together until the end. The approach usually taught is to separate the variable terms and constant terms. (The number of steps required is the same either way.)

The reason this is "no brain" is that it always works and requires no judgment as to what you add or subtract from where. Applying a little judgment as described above can make it so you're mostly working with positive numbers, but the method works whether the numbers are positive or negative.

6 0
4 years ago
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