Question

Please help!!!

Answer 1

Answer:

$64^{\circ}$

Step-by-step explanation:

$~~~~~~\cos \angle E = \sin \angle F\\\\\implies \cos 26^{\circ} = \sin \angle F\\ \\\implies \angle F = \sin^{-1} \left( \cos 26^{\circ} \right)\\\\\implies \angle F = \sin^{-1} \left(\sin(90^{\circ}-26^{\circ}) \right)\\\\\implies \angle F = \sin^{-1} \left( \sin 64^{\circ} \right)\\\\\implies \angle F = 64^{\circ}$