Answer:
4 consecutive goals
Step-by-step explanation:
If 3 of last 10 field goals = 30%
Which is equivalent to
(Number of goals scored / total games played) * 100%
(3 / 10) * 100% = 30%
Number of consecutive goals one has to score to raise field goal to 50% will be:
Let y = number of consecutive goals
[(3+y) / (10+y)] * 100% = 50%
[(3+y) / (10+y)] * 100/100 = 50/100
[(3+y) / (10+y)] * 1 = 0.5
(3+y) / (10+y) = 0.5
3+y = 0.5(10 + y)
3+y = 5 + 0.5y
y - 0.5y = 5 - 3
0.5y = 2
y = 2 / 0.5
y = 4
Therefore, number of consecutive goals needed to raise field goal to 50% = 4
Answer:
ln
(
f
(
x
)
)
=
ln
(
a
)
+
x
ln
(
b
)
Step-by-step explanation:
that's the answer
Answer:
I think it's B
Step-by-step explanation: I hope that helps
Answer: 0.129
Step-by-step explanation:
Coach Collin's soccer team selected 16 girls from 124 girls who tried out for the team.
The fraction of girls selected to those who tried out in fraction form is:
= 16/124
The decimal form will be:
= 16 ÷ 124
= 0.129
Answer:
2x+2
Step-by-step explanation:
drop the ( ) and combine like terms