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erik [133]
2 years ago
9

For all real numbers a,b and c If a>b, then a+c___ b+c

Mathematics
1 answer:
Arlecino [84]2 years ago
4 0

-------------------------------------------------------------------------------------------------------------

Answer:  \textsf{a + c } > \textsf{ b + c}

-------------------------------------------------------------------------------------------------------------

Given: \textsf{a} > \textsf{b}

Find:  \textsf{a + c }\_\_\_ \textsf{ b + c}

Solution:  We know that a is greater than b and we also know that we are going to be adding c to both sides which means that both sides would increase by the same amount.  Therefore a + c would still be greater than b + c giving us the expression of a + c > b + c.

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the perimeter of a basketball court is 102 meters, and length is 6 meters longer than twice the width, what r length and width.
stepladder [879]
Perimeter = 2(l + w)

Thus,

102 = 2(l + w)

l = 6 + 2w

102 = 2( 6 + 2w + w)
102 = 12 + 4w +2 w
102 = 12 + 6w
90 = 6w

Thus, w = 15.

Length = 6 + 2w
= 6 + 30
= 36.

Thus, the length is 36 meters and width is 15 meters.
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3 years ago
What is the volume of the cube?
Jobisdone [24]
27 cubic inches
Because you multiply 3x3x3=27
4 0
3 years ago
Write the sum using summation notation, assuming the suggested pattern continues. 6, -18, 54, -162, +… Is this sequence arithmet
telo118 [61]

Answer:

Hello,

This sequence is geometric with a ratio of -3

the first term is 6

Step-by-step explanation:

u_1=6\\u_2=-18=6*(-3)=u_1*(-3)\\u_3=54=-18*(-3)=u_2*(-3)=u_1*(-3)^2\\u_4=-162=u_3*(-3)=u_1*(-3)^3\\\\...\\u_{n+1}=u_1*(-3)^n\\\\\displaystyle \sum\limits^\infty _{i=1}u_i = \lim_{n \to \infty} \sum\limits^n _{i=1}u_1*(-3)^{i-1}\\=6*\lim_{n \to \infty} \sum\limits^\infty _{i=1}(-3)^{i-1}\\=6*\frac{1-(-3)^n}{1-(-3)} \\=\dfrac{3}{2} *({1-(-3)^n)\\

serie does not converge.

7 0
3 years ago
Help with math plz! Giving brainlist
Semmy [17]

#1

= x^5 y^7z^2 ∜z^2

 

#2

x/y √ 5/2

 

#3

= y - 7√2y + √2y -14

= y - 6√2y – 14

 

#4

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<span>= 1/x</span>

3 0
3 years ago
Perform the following operations and write the answers in radical form.
strojnjashka [21]

Given:

Part A: \sqrt{7}+\sqrt{3}+\sqrt{98}-\sqrt{18}

Part B: 3 \sqrt{5}-3 \sqrt{11}+2 \sqrt{121}-3 \sqrt{90}

To find:

The simplified radical form.

Solution:

Part A: \sqrt{7}+\sqrt{3}+\sqrt{98}-\sqrt{18}

\sqrt{98}=\sqrt{7^2 \times 2} =7 \sqrt{2}

\sqrt{18}=\sqrt{3^2 \times 2} =3 \sqrt{2}

Substitute these in the given expression.

\sqrt{7}+\sqrt{3}+\sqrt{98}-\sqrt{18}=\sqrt{7}+\sqrt{3}+7\sqrt{ 2}-3\sqrt{ 2}

Add or subtract the coefficient of same radical.

                                    =\sqrt{7}+\sqrt{3}+(7-3)\sqrt{ 2}

                                    =\sqrt{7}+\sqrt{3}+4\sqrt{ 2}

Part B: 3 \sqrt{5}-3 \sqrt{11}+2 \sqrt{121}-3 \sqrt{90}

2 \sqrt{121}=2\sqrt{11^2}

           =2\times 11

           = 22

3 \sqrt{90}=3\sqrt{3^2 \times 10}

           =3\times 3 \sqrt{10}

           =9 \sqrt{10}

Substitute these in the given expression.

3 \sqrt{5}-3 \sqrt{11}+2 \sqrt{121}-3 \sqrt{90}=3 \sqrt{5}-3 \sqrt{11}+22-9 \sqrt{10}

8 0
3 years ago
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