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MrRa [10]
2 years ago
8

Find the length of the third side. If necessary, round to the nearest tenth.

Mathematics
2 answers:
viva [34]2 years ago
5 0

Answer:

the question states if necessary, round the nearest tenth and by using the pythagoras theorem the answer should be 10 since its 9.21 and its nearest 10th is 10? im not quite sure though

lina2011 [118]2 years ago
4 0

Answer:

≈ 9.2

Step-by-step explanation:

using Pythagoras' identity in the right triangle

the square on the hypotenuse is equal to the sum of the squares on the other 2 sides.

let x be the third side ( hypotenuse ) , then

x² = 7² + 6² = 49 + 36 = 85 ( take square root of both sides )

x = \sqrt{85} ≈ 9.2 ( to the nearest tenth )

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Help please im struggling.
Hunter-Best [27]

Answer:

D. 2,2

Step-by-step explanation:

The midpoint just means the point in the middle of the line, and if you count inwards from each of the points, you'll find that D is the midpoint.

4 0
2 years ago
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The width of the rectangle
Nikolay [14]

Answer:

84cm^2

Step-by-step explanation:

P=2l+2w

We are given,

P=40cm

l=2w+2

Plug these into the first formula and solve for the dimensions,

length and width, of the rectangle:

40=2(2w+2)+2w              Simplify

40=4w+4+2w

40=6w+4

36=6w

6=w OR the width is 6cm, therefore,

the length is

l=2(6)+2

l=14cm

To calculate the area of a rectangle, A=lw,

plug the length,14cm, and the width, 6cm, into this formula

A=(14)(6)

A=84cm2 OR the area of the rectangle is 84cm^2

7 0
3 years ago
24.7 divided 10^3 <br><br> Please help
aivan3 [116]

Answer:

2.47 yeahhh I think...........

Step-by-step explanation:

2.47 i think

7 0
2 years ago
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The volume of a rectangular prism is b3 + 8b2 + 19b + 12 cubic units, and its height is b + 3 units. The area of the base of the
omeli [17]
Given:

The volume of the rectangular prism is 

b^{3}+8 b^{2} +19b+12,

the height is h=(b+3)

1. The volume of a rectangular prism is (base area)*height

also, notice that the volume is a third degree polynomial, the height is a 1st degree polynomial, so the base area must be a 2nd degree polynomial, whose coefficients we don't know yet.
Let this quadratic polynomial be (mb^{2}+nb+k)

 
2

b^{3}+8 b^{2} +19b+12=(mb^{2}+nb+k)*(b+3)


notice that  b^{3} is the product of the largest 2 terms: mb^{2} and b, so m must be 1

also, notice that 12 is the product of the constants, k and 3

so k*3=12, this means k=4

3
we write the above equality again:

b^{3}+8 b^{2} +19b+12=(b^{2}+nb+4)*(b+3)


(b^{2}+nb+4)(b+3)= b^{3}+3 b^{2} +nb^{2}+3nb+4b+12

== b^{3}+(n+3)b^{2}+(3n+4)b+12


4
now compare the coefficient with the left side:

8 b^{2}=(n+3)b^{2}

8=n+3

n=5


substituting n=5: 

the base area is b^{2}+5b+4

Answer: b^{2}+5b+4


3 0
3 years ago
What is the area of this triangle in the coordinate plane?
Mars2501 [29]

Answer:

6 units

Step-by-step explanation:

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3 years ago
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