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SVETLANKA909090 [29]
2 years ago
12

Fifteen years ago, everyone didn't have a cell phone. Anyone developing an app would not have found many users. Today, the exist

ence of mobile apps is one of the reasons why smartphones are so popular today. These apps make phones and tablets smart, in terms of functionality and features. The app market is seeing hundreds of new applications introduced every day. This example shows that _______.
Computers and Technology
1 answer:
yarga [219]2 years ago
6 0

Answer:

Are there any options?

Explanation:

The world is frequently coming in with better and more advanced technologies. More people are entering the digital world every day. The pace at which disruptive technologies are arriving is accelerating – and they’re changing how we live. The same technologies are giving rise to new business models. Example of development in the past 15 years- A.I.

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Jordan has been asked to help his company find a way to allow all the workers to log on to computers securely but without using
lana66690 [7]

Answer:

Webcam

Explanation:

A webcam is mainly used for taking images or videos from the computer. the webcam is a combination of two basic words i.e. web and camera. webcam can be connected to any computer via USB. It can be mounted on the desktop and sometimes it comes inbuilt on the laptops.

A webcam is also used for face recognition function to login to a computer system.

so according to the scenario, the most appropriate answer is a webcam.

6 0
3 years ago
Output each floating-point value with two digits after the decimal point, which can be achieved as follows:
sdas [7]

Answer:

The modified program in Python is as follows:

import math

paint_colors = {'red': 35,'blue': 25,'green': 23}

wall_height = int(input('Enter wall height (feet):\n'))

wall_width = int(input('Enter wall width (feet):\n'))

area = wall_height*wall_width

print('Wall area:',area,'square feet')

paint_needed = area/350.0

print('Paint needed: {:.2f} gallons'.format(paint_needed))

print('Cans needed:',round(paint_needed),'can(s)')

color = input("Choose a color to paint the wall: ")

print("Cost of purchasing", color, "paint: $",paint_colors[color])

Explanation:

The italicized are given from the question [unchanged]

<em>import math</em>

<em> paint_colors = {'red': 35,'blue': 25,'green': 23} </em>

<em>wall_height = int(input('Enter wall height (feet):\n')) </em>

This gets input for width

wall_width = int(input('Enter wall width (feet):\n'))

Calculate the wall area

area = wall_height*wall_width

Print the calculated wall area

print('Wall area:',area,'square feet')

Calculate the amount of paint needed

paint_needed = area/350.0

Print the amount of paint needed to 2 decimal places

print('Paint needed: {:.2f} gallons'.format(paint_needed))

Print the amount of can needed to nearest integer

print('Cans needed:',round(paint_needed),'can(s)')

Prompt user for color of paint [here, we assume the user input is correct]

color = input("Choose a color to paint the wall: ")

Prints the corresponding amount for the color

print("Cost of purchasing", color, "paint: $",paint_colors[color])

3 0
2 years ago
How long before a speech should you begin practicing?
hichkok12 [17]

Answer:

D

Explanation:

4 0
3 years ago
Read 2 more answers
Complete the steps to evaluate the following
kirill115 [55]

Answer:

log base 3a= -0.631.log a/3 base 3

Now, -log m= log 1/m

hence,

log base 3a= 0.631.log 3/a base 3

log base 3a/log 3/a base 3 =0.631

log base 3 ( a.3/a) =.631 since, log m/logn =log n(m)

log base 3 3=0.631

Hence, answer is log base 3 3=0.631

Explanation:

Please check the answer section.

3 0
3 years ago
Read 2 more answers
The purpose of this assignment is to determine a set of test cases knowing only the function’s specifications, reported hereaf
Nesterboy [21]

Answer:

The program is written using PYTHON SCRIPT below;

N=int(input(" Enter number of Rows you want:"))

M=[] # this for storing the matrix

for i in range(N):

l=list(map(int,input("Enter the "+str(i+1)+" Row :").split()))

M.append(l)

print("The 2D Matrix is:\n")

for i in range(N):

print(end="\t")

print(M[i])

W=[] # to store the first non zero elemnt index

T=[] # to store that value is positive or negative

L=len(M[0])

for i in range(N):

for j in range(L):

if (M[i][j]==0):

continue

else:

W.append(j) # If the value is non zero append that postion to position list(W)

if(M[i][j]>0): #For checking it is positive or negative

T.append(+1)

else:

T.append(-1)

break

print()

print("The first Non Zero element List [W] : ",end="")

print(W)

print("Positive or Negative List [T] : ",end="")

print(T)

Explanation:

In order for the program to determine a set of test cases it takes in input of 2D matrix in an N numbet of rows.

It goes ahead to program and find the column index of the first non-zero value for each row in the matrix A, and also determines if that non-zero value is positive or negative. The If - Else conditions are met accordingly in running the program.

5 0
3 years ago
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