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1 year ago

PLEASE HELP! Find the surface area of the right triangular prism.

Mathematics

1 answer:

slega [8]1 year ago

4 0

Answer:

1200 in²

Step-by-step explanation:

The surface area of the prism is the sum of the lateral area and the areas of the bases.

<h3>lateral area</h3>

The lateral area is the total area of the three rectangular faces. It can be computed from ...

LA = Ph

where P is the perimeter of the triangular base, and h is the height of the prism (the distance between triangular bases).

The perimeter is the sum of the edge lengths of the base:

P = 30 in + 17 in + 17 in = 64 in

Then the lateral area is ...

LA = (64 in)(15 in) = 960 in²

The two bases are congruent triangles, so have a total area of ...

A = 2(1/2bh) = bh

where b is the base of the triangle, and h is its height.

A = (30 in)(8 in) = 240 in²

<h3>total surface area</h3>

The sum of lateral area and base area is ...

total area = (960 in²) +(240 in²) = 1200 in²

The surface area of the triangular prism is 1200 square inches.

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Dennis_Churaev [7]

Answer:

Tax= $ 7,173.5

Step-by-step explanation:

Her taxable income is $ 43,000 which lies in the tax category $ 31,850 to

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25 % of $ 11,150= $ 2,787.5

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Step-by-step explanation:

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3 years ago

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Step-by-step explanation:

that's for Part B

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3 years ago

Describe the pattern of decay for the sequance.

Georgia [21]

256-192= 64

192-144=48

144-108=36

108-81=27

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60.8-45.6=15.2

45.6-34.2= 11.4

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2 years ago

At the Foremost State Bank the average savings account balance in 2012 was $1900. A random sample of 45 savings account balanes

lakkis [162]

Answer:

The calculated |t| = |-26.517|=26.517 > 2.326 at 0.01 level of significance

Null hypothesis is rejected at 0.01 level of significance

There is difference between mean savings account balance in 2013 is different from the mean savings account balance in 2012

Step-by-step explanation:

<u><em>Step(i)</em></u>:-

Mean of the Population = 1900

Given random sample size 'n' = 45

Mean of the sample x⁻ = 1000

Standard deviation of the sample = 225

<u><em>Null Hypothesis</em></u>:-

There is no difference between mean savings account balance in 2013 is different from the mean savings account balance in 2012.

<u><em>Alternative Hypothesis</em></u> :-

There is difference between mean savings account balance in 2013 is different from the mean savings account balance in 2012

<u><em>Step(ii</em></u>):-

Test statistic

$t = \frac{x^{-}-mean }{\frac{S.D}{\sqrt{n} } }$

$t = \frac{1000-1900 }{\frac{225}{\sqrt{45} } }$

t = -900 /33.54 = -26.517

|t| = |-26.517|=26.517

Degrees of freedom

γ = n-1 = 45-1 =44

t₍₀.₀₁ , ₄₄₎ = 2.326

The calculated |t| = |-26.517|=26.517 > 2.326 at 0.01 level of significance

Null hypothesis is rejected at 0.01 level of significance

There is difference between mean savings account balance in 2013 is different from the mean savings account balance in 2012

4 0

2 years ago

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Hope this helps!

8 0

2 years ago