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AnnyKZ [126]
1 year ago
10

which one of the following will reach every element in the array a? 1. for(int i = 0; i <= a.length; i++) 2. for(int i = 0; i

< a.length; i++) 3. for(int i = 1; i <= a.length; i++) 4. for(int i= 1-1 ; i < a.length; i++)
Computers and Technology
1 answer:
andrey2020 [161]1 year ago
4 0

Answer:

You can simplify the problem down by recognizing that you just need to keep track of the integers you've seen in array that your given. You also need to account for edge cases for when the array is empty or the value you get would be greater than your max allowed value. Finally, you need to ensure O(n) complexity, you can't keep looping for every value you come across. This is where the boolean array comes in handy. See below -

public static int solution(int[] A)

{

int min = 1;

int max = 100000;

boolean[] vals = new boolean[max+1];

if(A.length == 0)

return min;

//mark the vals array with the integers we have seen in the A[]

for(int i = 0; i < A.length; i++)

{

if(A[i] < max + 1)

vals[A[i]] = true;

}

//start at our min val and loop until we come across a value we have not seen in A[]

for (int i = 1; i < max; i++)

{

if(vals[i] && min == i)

min++;

else if(!vals[i])

break;

}

if(min > max)

return max;

return min;

}

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In a batch operating system, three jobs are submitted for execution. Each job involves an I/O activity, CPU time and another I/O
Ilia_Sergeevich [38]

Answer:

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b) CPU utilization for multiprogramming system = 41.379%

Explanation:

IO time = total time – CPU time

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total time= 23ms

IO time = 23-3 = 20ms ,

For JOB 2

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total = 29ms

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For JOB 3  

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total = 14ms

IO time = 14-10 =10ms  

1.) In uniprogramming system, operations are performed sequentially

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CPU utilization =(3+5+4) / (23+29+14)

CPU utilization =0.182 or 18.2%

2) In multiprogramming system, jobs wait for the CPU to get free while performing IO operations concurrently

steps followed by the os

1. IO for 1st job                           at 0ms

2. IO for 2nd job                          at 0ms

3. IO for 3rd job                          at 0ms

4. CPU time for 3rd job              at 5ms

5. Next IO job for 3rd job           at 9ms END at 14ms

6. CPU time for 1st job              at 9ms

7. Next IO job for 1st job           at 14ms END at 23ms

8. CPU time for 2nd job             at 14ms

9. Next IO job for 2nd job          at 15ms END at 29ms

CPU time is 3+5+4 =12ms

Total execution time = 29ms

CPU utilization = 12*100/29= 41.379%

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