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natali 33 [55]
2 years ago
15

Hey! A bit stumped on this one

Mathematics
1 answer:
Dahasolnce [82]2 years ago
6 0

Answer:

0,4,8

Step-by-step explanation:

We need to replace x with 1, 2, and 3 one by one in the given equations to find the value of y for each value:

<em>for x = 1</em>

y = 4*1 - 4 and y = 0 in this case

<em>for x = 2</em>

y = 4*2 - 4

y = 8 - 4 and y = 4 in this case

<em>for x = 3</em>

y = 4*3 - 4

y = 12 - 4 and y = 8 in this case

So the answer is

0,4,8

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Yes, 60° is right.

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How do you rearrange the equation (2x) /(4pi) +((1-x) /2) =0 to solve for x?
USPshnik [31]
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Then we will multiply both sides of the equation by 2 π :
x + π ( 1 - x ) = 0
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3 0
4 years ago
Use the quadratic formula <br> 9x^2+3x-1=0
ASHA 777 [7]

Answer:

9x2+3x−1=0

Step 1: Use quadratic formula with a=9, b=3, c=-1.

x= −b±√b2−4ac

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2(9)

x= −3±√45

18

x= −1

6

+

1

6

√5 or x=

−1

6

+

−1

6

√5

Answer:

x=

−1

6

+

1

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√5 or x=

−1

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5 0
3 years ago
What the heck do i do with this
Ad libitum [116K]
Use the law of cosines to find a: a^2=b^2+c^2-2bc (cos(A))

So to use the given numbers you get: a^2=27^2+45^2-2(27)(45)(cos(53))

Which would come out to equal about 35.94

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7 0
3 years ago
Read 2 more answers
A line has a gradient of 8 and passes through the point (2,3). Find the equation of the line
yanalaym [24]

                  - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

\large\blue\textsf{\textbf{\underline{\underline{Question:-}}}}

        A line has a gradient of 8 and passes through (2, 3). What is the line's equation?

\large\blue\textsf{\textbf{\underline{\underline{Answer and How to solve:-}}}}

       With the provided information, we can write the equation of the line in point-slope form:

          \sf{y-y_1=m(x-x_1)}

<u>Where</u>

y₁ = the y-coordinate of the point

m = gradient or slope

x₁ = the x-coordinate of the point

Substitute the values:-

\sf{y-3=8(x-2)}

We have our equation in point-slope form.

If you need the equation in slope-intercept form, please consult the following steps.

\sf{y-3=8(x-2)}

Use the distributive property and multiply 8 times x and -2:-

\sf{y-3=8x-16}

Now, add 3 on both sides:-

\dashrightarrow\star\bigstar\boxed{\sf{y=8x-13}}

<h3>Good luck.</h3>

              - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

6 0
2 years ago
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