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zubka84 [21]
2 years ago
14

I need some math help please

Mathematics
1 answer:
Yuliya22 [10]2 years ago
5 0

Answer:

A.Pi

Step-by-step explanation:

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Original price $45.00; markdown 22%
Setler79 [48]

First convert 22 to decimal form. You do this by dividing the percent by 100.
22 / 100 = .22

Then multiply the dollar amount by the percentage in decimal form.

$45 * .22 = $9.9

So 22% of $45 is $9.9.

Then you subtract $9.9 from $45.

$45 - $9.9 = $35.1




4 0
3 years ago
Can someone please help​
salantis [7]

Answer:

acute

Step-by-step explanation:

4 0
3 years ago
What is the unit rate of 183 miles in three hours
Ber [7]
61 miles per hour, because if you divide 183/3 you will get 61.
3 0
3 years ago
Read 2 more answers
The Pacific halibut fishery has been modeled by the differential equation dy dt = ky 1 − y K where y(t) is the biomass (the tota
Dafna1 [17]

Answer:

a. The biomass weighs 2.30 * 10^7 kg after a year

b. It'll take 2.56 years to get to 4*10^7kg

Step-by-step explanation:

a.

k = 0.78,K = 6E7 kg

Given

dy/dt = ky(1- y/K)

Make ky dt the subject of formula

ky dt = dy/(1-y/K) --- make k dt the subject of formula

k dt = dy/(y(1-y/K))

k dt = K dy / y(K-y)

k dt = ((1/y) + (1/(K-y)))dy ---- integrate both sides

kt + c = ln(y/(K-y))

Ce^(kt) = y/(K-y)

Substitute the values of k and K

Ce^(0.78t) = y/(6*10^7 - y) ----- (1)

Given that y(0) = 2 * 10^7kg

(1) becomes

Ce^(0.78*0) = (2 * 10^7)/(6*10^7 - 2*10^7)

Ce° = (2*10^7)/(4*10^7

C = 2/7

Substitute 2/7 for C in (1)

2/7e^0.78t = y/(6*10^7 - y) ---(2)

We're to find the biomass a year later

So, t = 1

2/7e^0.78 = y/(6*10^7 - y)

0.62 = y/(6*10^7 - y)

y = 0.62(6*10^7 - y)

y = 0.62*6*10^7 - 0.62y

y + 0.62y = 0.62*6*10^7

1.62y = 0.62*6*10^7

1.62y = 3.72 * 10^7

y = 2.30 * 10^7kg.

Hence, the biomass weighs 2.30 * 10^7 kg after a year

b.

Here, we're to calculate the time it'll take the biomass to get to 4*10^7 kg

Substitute 4*10^7 for y in (2)

2/7e^0.78t = 4*10^7/(6*10^7 - 4*10^7)

2/7e^0.78t = 4*10^7/2*10^7

2/7e^0.78t = 2

e^0.78t = (2*7)/2

e^0.78t = 2

t = 2 * 1/0.78

t = 2.56 years

Hence, it'll take 2.56 years to get to 4*10^7kg

8 0
3 years ago
An empty 6-gal water jug weighs 0.5 lb. With 3 c of water inside, the jug weighs 2 lb. Which equation models the jug’s weight y
nikdorinn [45]
The slope would be 2/3 because that would leave pounds when multiplied by cups.

add 0.5 for the weight of the water jug

y = (2/3)x + 0.5
3 0
3 years ago
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