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yawa3891 [41]
2 years ago
8

How much is 3 quaters + three dimes + 5 cents equals?I'm trying to make a dollar​

Mathematics
2 answers:
beks73 [17]2 years ago
7 0
It equals 1 dollar and 10 cents
saw5 [17]2 years ago
6 0

Answer:

$1.10

Step-by-step explanation:

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What is 9x+210=4x+140
Svetradugi [14.3K]

Answer:Final answer: (45,30)

Step-by-step explanation:

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4 years ago
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Jenny ran 6,715 meters in 8.3 minutes. Johnny ran 1,455 meters in 2.1 minutes. Who was faster and by how much?​
Viefleur [7K]

Answer:  Jenny was faster by 116.17

Step-by-step explanation: Jenny: 809.03 meters a minute

Johnny: 692.86 meters a minute

7 0
3 years ago
Calculate the distance between the points (-8,1) and (0,7)
guapka [62]

Answer:

10 units

Step-by-step explanation:

\boxed{distance =   \sqrt{(x2 - x1)^{2}  + (y2 - y1)^{2} }}

Using the distance formula above,

distance between the 2 points

=  \sqrt{[0 - ( -  8)]^{2} + (7 - 1)^{2}  }  \\  =  \sqrt{(0 + 8)^{2} + 6^{2}  }  \\  =  \sqrt{ {8}^{2}  + 36}  \\  =  \sqrt{64 + 36}  \\  =  \sqrt{100}  \\  = 10 \: units

8 0
4 years ago
Find the answer for 1 & 2
svp [43]
The height of the deck if it is parallelogram H ≈ 6.13

7 0
3 years ago
A simple random sample from a population with a normal distribution of 103 body temperatures has x overbarequals98.90degrees Upp
Shtirlitz [24]

Answer:

98.90-1.984\frac{0.62}{\sqrt{103}}=96.98    

98.90+ 1.984\frac{0.62}{\sqrt{103}}=100.82    

The 95% confidence interval would be given by (96.98;100.82)    

Step-by-step explanation:

Information given

\bar X=98.90 represent the sample mean

\mu population mean (variable of interest)

s=0.62 represent the sample standard deviation

n=103 represent the sample size  

Confidence interval

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

The degrees of freedom are given by:

df=n-1=103-1=102

Since the Confidence is 0.95 or 95%, the significance is \alpha=0.05 and \alpha/2 =0.025, and the critical value for this case would be t_{\alpha/2}=1.984

And replacing we got:

98.90-1.984\frac{0.62}{\sqrt{103}}=96.98    

98.90+ 1.984\frac{0.62}{\sqrt{103}}=100.82    

The 95% confidence interval would be given by (96.98;100.82)    

8 0
4 years ago
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