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KatRina [158]
2 years ago
5

Can someone solve this for me?

Mathematics
1 answer:
Helga [31]2 years ago
5 0

well, we know it's a rectangle, so that means the sides JK = IL and JI = KL, so

\stackrel{JK}{3x+21}~~ = ~~\stackrel{IL}{6y}\implies 3(x+7)=6y\implies x+7=\cfrac{6y}{3} \\\\\\ x+7=2y\implies \boxed{x=2y-7} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{JI}{6y-6}~~ = ~~\stackrel{KL}{2x+20}\implies 6(y-1)=2(x+10)\implies \cfrac{6(y-1)}{2}=x+10 \\\\\\ 3(y-1)=x+10\implies 3y-3=x+10\implies \stackrel{\textit{substituting from the 1st equation}}{3y-3=(2y-7)+10} \\\\\\ 3y-3=2y+3\implies y-3=3\implies \blacksquare~~ y=6 ~~\blacksquare ~\hfill \blacksquare~~ \stackrel{2(6)~~ - ~~7}{x=5} ~~\blacksquare

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Xz=58 and yz=23.1 find xy
Pachacha [2.7K]

Step-by-step explanation:

XZ = 58

YZ = 23.1

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XY = 81 .1

4 0
2 years ago
How am I supposed to do question 4???
salantis [7]

Answer:

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3 0
2 years ago
In Exercise, find the derivative of the function.<br> y = 3ex - xex
nevsk [136]

Answer:

the question is incomplete, the complete question is "find the derivative of the function y=3e^{x}-xe^{x}"

answer: \frac{dy}{dx}=(2-x)e^{x}.

Step-by-step explanation:

From the equation,  y=3e^{x}-xe^{x}, we approach the question using the differentiation of a product and differentiation of a sum simultaneously,

the differentiation of a sum is express as

f(x)=u(x)+v(x)+.....w(x) then

\frac{df(x)}{dx}=\frac{du(x)}{dx}+\frac{dv(x)}{dx}+...\frac{dw(x)}{dx}.\\

For the differentiation of a product we have

 f(x)=u(x)v(x), then

\frac{df(x)}{dx}=\frac{dv(x)}{dx}u(x)+\frac{du(x)}{dx}v(x)

hence if we go by the formula we arrive at

for   y=3e^{x}

let u(x)=3 hence du/dx=0 and

v(x)=e^{x} and \frac{dv(x)}{dx}=e^{x}

hence \frac{dy}{dx}=3e^{x}+0e^{x}\\\frac{dy}{dx}=3e^{x}---equation 1\\

Also for y=-xe^{x}\\\frac{dy}{dx}=-e^{x}-xe^{x}---equation 2.

if we add equation 1 and equation 2 we arrive at

\frac{dy}{dx}=3e^{x}-e^{x}-xe^{x}\\\frac{dy}{dx}=(3-1-x)e^{x}\\\frac{dy}{dx}=(2-x)e^{x}.

4 0
3 years ago
Solve this linear system by graphing. Check the solution. <br> 3x+y=11<br> x-2y=6
alexandr402 [8]
In this system of equations, I'll do elimination. Ok, so what we are trying to do is to eliminate a variable, but we can't. So since -2y is negative, and y has a coefficient of 1 and is positive, let's multiply the first whole equation by 2.
2 times (3x+y=11) is 6x+2y=22. (I just used distributive property.) Now let's add from left to right.
6x plus x is 7x, 2y plus -2y is 0, and 22 plus 6 is 28. Now we have this simple equation, 7x=28. We can simply divide each side by 7, to get x as 4. So x=4 in this set of equations. Now all we need to do is plug x in the equation then solve for y. For this system of equations, I'll use the first equation, because it is easier. So I'll plug x as 4 into the equation to get 12+y=11. Now we can simply solve for y. 11-12 is -1, so y must equal -1. So y=-1. Therefore, x=4 and y=-1. Hope I helped.
6 0
3 years ago
Read 2 more answers
What is the measure of x?<br> A. 144°<br> B. 72°<br> C. 36°<br> D. 18°
dolphi86 [110]
Here, 4x + x =180  [ Supplementary angles ]
5x = 180
x = 180/5
x = 36

In short, Your Answer would be Option C

Hope this helps!
4 0
4 years ago
Read 2 more answers
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