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kati45 [8]
2 years ago
7

How to write Q={1,2,3,5} in set builder form?​

Mathematics
1 answer:
blagie [28]2 years ago
8 0

Answer:

{x:x is a natural number less than 6}

Step-by-step explanation:

Set builder is a type of set where we have to represent any value inside a set

by using the variable x, v, b, a, c etc.

Eg A={1,2,3,4}

For eg {a: a is a natural number less than 5}

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La respuesta del ejercicio numero 7
andriy [413]
In a math book??? Need more explanation
8 0
3 years ago
Larry buys a tent that is on sale for 25% off the original price. The original price is $80 more than the sale price. What is th
myrzilka [38]

Answer:

The original price of the tent = $320

Step-by-step explanation:

Let the original price be =$ x

Discount offered  = 25% of the orignal price = \frac{25}{100}\times x=0.25\times x =\$ 0.25x

Original price is $80 more than sale price

Discount = Original price - Sale price = $80

So, we have

0.25x=80

We need to solve for x to find original price

Dividing both sides by 0.25

\frac{0.25}{0.25}x=\frac{80}{0.25}\\x=\$320

∴ The original price of the tent = $320

3 0
3 years ago
What is the solution of x=2+ square root x-2?
alex41 [277]

So I'm going to assume that this question is asking for <u>non extraneous solutions</u>, or solutions that are found in the equation <em>and</em> are valid solutions when plugged back into the equation. So firstly, subtract 2 on both sides of the equation:

x-2=\sqrt{x-2}

Next, square both sides:

(x-2)^2=x-2\\(x-2)(x-2)=x-2\\x^2-4x+4=x-2

Next, subtract x and add 2 to both sides of the equation:

x^2-5x+6=0

Now we are going to be factoring by grouping to find the solution(s). Firstly, what two terms have a product of 6x^2 and a sum of -5x? That would be -3x and -2x. Replace -5x with -2x - 3x:

x^2-2x-3x+6=0

Next, factor x^2 - 2x and -3x + 6 separately. Make sure that they have the same quantity on the inside of the parentheses:

x(x-2)-3(x-2)=0

Now you can rewrite the equation as (x-3)(x-2)=0

Now, apply the Zero Product Property and solve for x as such:

x-3=0\\x=3\\\\x-2=0\\x=2

Now, it may appear that the answer is C, however we need to plug the numbers back into the original equation to see if they are true as such:

2=2+\sqrt{2-2}\\2=2+\sqrt{0}\\2=2+0\\2=2\ \textsf{true}\\\\3=2+\sqrt{3-2}\\3=2+\sqrt{1}\\3=2+1\\3=3\ \textsf{true}

Since both solutions hold true when x = 2 and x = 3, <u>your answer is C. x = 2 or x = 3.</u>

8 0
3 years ago
Select all equations whose graphs have a vertex with x-coordinate 2
iren2701 [21]

Answer:

C

Step-by-step explanation:

because you have to foil then do -b/2a

8 0
3 years ago
Solve the following quadratic equation for all values of xx in simplest form. 3(x+1)²-15=-12​
suter [353]

Answer:

x = 0, -2

Step-by-step explanation:

3 0
2 years ago
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