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SVETLANKA909090 [29]
2 years ago
14

The following table shows the total number of quizzes taken in high school. how many quizzes are taken per week?

Mathematics
1 answer:
dybincka [34]2 years ago
6 0
The following table shows the total number of quizzes taken in high school. how many quizzes are taken per week?
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In the manufacturing division of a particular company, there are 68 hourly employees and 30 for salaried employees to employees
umka21 [38]
I’m yeh manufacturing it’s with me 30p because it just will I think that was it is I need point
5 0
3 years ago
The table and the graph below each show a different relationship between the same two variables, x and y:
gavmur [86]
The value of y would be 20 times more valuable than 12 because the pattern for this table is y=20x. Let me know if I'm right :)
7 0
3 years ago
What is the quotient of (x3 - 3x2 + 5x – 3) = (x - 1)?
IRINA_888 [86]

Note: Consider "÷" sign instead of "=".

Given:

(x^3-3x^2+5x-3)\div (x-1)

To find:

The quotient.

Solution:

We have,

(x^3-3x^2+5x-3)\div (x-1)

It can be written as

=\dfrac{x^3-3x^2+5x-3}{x-1}

Splitting the middle terms, we get

=\dfrac{x^3-x^2-2x^2+2x+3x-3}{x-1}

=\dfrac{x^2(x-1)-2x(x-1)+3(x-1)}{x-1}

Taking out the common factor (x-1), we get

=\dfrac{(x-1)(x^2-2x+3)}{x-1}

Cancel the common factors.

=x^2-2x+3

The quotient is x^2-2x+3.

Therefore, the correct option is D.

7 0
3 years ago
Read 2 more answers
The music festival took 77 days to plan.
liraira [26]
77 days turned into weeks means that you have to divide by seven.
77/7 = 11.
It took eleven weeks to plan (Answer choice D)
8 0
3 years ago
Read 2 more answers
If m and n are the zeroes of the polynomial 6y 2 -7y – 2, find a polynomial whose zeroes are 1/m and 1/n
denis-greek [22]

Answer:

y^2-\frac{7}{2}y+3

Step-by-step explanation:

Given polynomial is,

6y² - 7y - 2

Fro the zeros of the given polynomial,

6y² - 7y - 2 = 0

6y² - 4y - 3y - 2 = 0

2y(3y - 2) - 1(3y - 2) = 0

(2y - 1)(3y - 2) = 0

(2y - 1) = 0

y = \frac{1}{2}

(3y - 2) = 0

y = \frac{2}{3}

Therefore, zeros of this polynomial are m = \frac{1}{2} and n = \frac{2}{3}

If a polynomial has zeros as \frac{1}{m} and \frac{1}{n} then the zeros will be \frac{3}{2} and 2.

Polynomial will be,

(y-\frac{3}{2})(y-2)

= y(y-2)-\frac{3}{2}(y-2)

= y^2-2y-\frac{3}{2}y+3

= y^2-\frac{7}{2}y+3

7 0
2 years ago
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