Answer:
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Answer:
14.8% of H2O2
Explanation:
Based on the redox reaction of H2O2/MnO4- is:
2MnO4- + 5H2O2 + 6H+ ⇄ 2Mn2+ + 5O2 + 8H2O
<em>2 moles of KMnO4 react with 5 moles of H2O2</em>
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To solve this question we need to find the moles of KMnO4 until reach the endpoint. Using the balanced reaction, we can find the moles of H2O2 that must be converted to grams using its molar mass -Molar mass H2O2: 34.015g/mol-:
<em>Moles KMnO4:</em>
0.0297L * (1.4686eq/L) = 0.04362eq MnO4- * (1mol / 5eq) = 0.008723 moles MnO4-
<em>Moles H2O2:</em>
0.008723 moles MnO4- * (5mol H2O2 / 2mol MnO4-) = 0.02181 moles H2O2
<em>Mass H2O2:</em>
0.02181 moles H2O2 * (34.015g/mol) = 0.7418g H2O2
<em>%:</em>
0.7418g H2O2 / 5.0mL * 100
<h3>14.8% of H2O2</h3>
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