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olga_2 [115]
1 year ago
6

Please help me with this

Mathematics
2 answers:
denis-greek [22]1 year ago
7 0

Answer:

10 percent

Step-by-step explanation:

look closl

Anettt [7]1 year ago
5 0

it's 10 percent ...................... 10%

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Please help thanks !
Kitty [74]

Answer:

option D

Step-by-step explanation:

x^{2} + y^{2} = 16\\\\x^{2} = 16- y^{2}

equation 2:

\frac{x^{2}}{4} - \frac{y^{2}}{25} = 1

so we have:

\frac{16- y^{2} }{4}-\frac{y^{2}}{25}= 1

7 0
3 years ago
Pls help!!!! Rewrite the expression. <br> 4+4+5x2x5+(3+3+3)x6x6+2+2
Paha777 [63]

Answer:

386

Step-by-step explanation:

4+4+5x2x5+(3+3+3)x6x6+2+2

=4+4+5x2x5+9x6x6+2+2

=4+4+50+324+2+2

=386

8 0
3 years ago
Seeds are often treated with fungicides to protect them in poor-draining, wet environments. A small-scale trial, involving six t
alukav5142 [94]

Answer:

0.0076 = 0.76% probability that all five plants emerged from treated seeds

Step-by-step explanation:

The plants were chosen without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

In this question:

6 + 6 = 12 seeds, which means that N = 12

6 treated, which means that k = 6

Five sprouted, which means that n = 5

What is the probability that all five plants emerged from treated seeds?

This is P(X = 5). So

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

P(X = 5) = h(5,12,5,6) = \frac{C_{6,5}*C_{6,0}}{C_{12,5}} = 0.0076

0.0076 = 0.76% probability that all five plants emerged from treated seeds

3 0
3 years ago
At a race track you have the opportunity to buy a ticket that requires you to pick the first and second place horses in the firs
rewona [7]

Answer:

4032 different tickets are possible.

Step-by-step explanation:

Given : At a race track you have the opportunity to buy a ticket that requires you to pick the first and second place horses in the first two races. If the first race runs 9 horses and the second runs 8.

To find : How many different tickets are possible ?

Solution :

In the first race there are 9 ways to pick the winner for first and second place.

Number of ways for first place - ^9C_1=9

Number of ways for second place - ^8C_1=8

In the second race there are 8 ways to pick the winner for first and second place.

Number of ways for first place - ^8C_1=8

Number of ways for second place - ^7C_1=7

Total number of different tickets are possible is

n=9\times 8\times 8\times 7

n=4032

Therefore, 4032 different tickets are possible.

8 0
2 years ago
2 4/5 ÷ 2 1/5 =<br> (Please answer as a fraction)
svet-max [94.6K]

Answer:

1 3/11

Step-by-step explanation:

8 0
3 years ago
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