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irinina [24]
2 years ago
10

A mine elevator was at a depth of -120 feet. After 15 seconds, the mine elevator was at a depth of -30 feet. What expression can

be represented how to find the speed of the mine elevator in feet per second?
Mathematics
1 answer:
Dafna11 [192]2 years ago
4 0

Answer:

The answers to the given question are:

i.  The equipment elevator is at a depth of 176 feet (-176 feet), while the miner's elevator is at a depth of 210 feet (-210 feet) below the surface.

ii. The miner's elevator is deeper than that of the equipment.

The speed of an object is the rate at which the object moves.

i.e. speed =

Thus,

Speed of the equipment elevator = 4 feet per second

Speed of the miner's elevator = 15 feet per second.

Time of descent of the equipment elevator = 30 + 14

                                 = 44 seconds

So that, the distance of the elevator at this time is;

speed =

⇒ distance = speed x time

                  = 4 x 44

                  = 176

  distance = - 176 feet

The distance of the miner's elevator after 14 seconds is:

speed =

⇒ distance = speed x time

                 = 15 x 14

                 = 210

 distance = - 210 feet

Thus, after another 14 seconds, the equipment elevator is at a depth of 176 feet (-176 feet), while the miner's elevator is at a depth of 210 feet (-210 feet) below the surface.

Therefore, the miner's elevator is deeper than that of the equipment.

Step-by-step explanation:

done

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(4 x 10) + (2 x 104)<br> Give your answer in standard form
Goshia [24]

Answer: =248x

Step-by-step explanation: Hope this help :D

Let's simplify step-by-step.

4x(10)+2x(104)

=40x+208x

Combine Like Terms:

=40x+208x

=(40x+208x)

=248x

7 0
3 years ago
I dont know how to do this pls help ​
Alecsey [184]

Answer:

1) 225

2) 2304

Step-by-step explanation:

1)

Use geometric mean of legs

x = \sqrt{(16+9)^2 * 9^2} = \sqrt{25^2 * 9^2}  = 25 * 9 = 225

2)

Use geometric mean of altitude

x = \sqrt{(100-36)^2 * 36^2} = \sqrt{64^2 * 36^2} = 64 * 36 = 2304

5 0
3 years ago
For the function F defined by F(x)=x2−2x+4, find F(−2).
Kruka [31]

Answer:

12

Step-by-step explanation:

x^2-2x+4  replace -2 for x

-2^2-2(-2)+4

4+4+4

12

4 0
3 years ago
Read 2 more answers
Seventy percent of all vehicles examined at a certain emissions inspection station pass the inspection. Assuming that successive
NeX [460]

Answer:

(a) 0.343

(b) 0.657

(c) 0.189

(d) 0.216

(e) 0.353

Step-by-step explanation:

Let P(a vehicle passing the test) = p

                        p = \frac{70}{100} = 0.7  

Let P(a vehicle not passing the test) = q

                         q = 1 - p

                         q = 1 - 0.7 = 0.3

(a) P(all of the next three vehicles inspected pass) = P(ppp)

                           = 0.7 × 0.7 × 0.7

                           = 0.343

(b) P(at least one of the next three inspected fails) = P(qpp or qqp or pqp or pqq or ppq or qpq or qqq)

      = (0.3 × 0.7 × 0.7) + (0.3 × 0.3 × 0.7) + (0.7 × 0.3 × 0.7) + (0.7 × 0.3 × 0.3) + (0.7 × 0.7 × 0.3) + (0.3 × 0.7 × 0.3) + (0.3 × 0.3 × 0.3)

      = 0.147 + 0.063 + 0.147 + 0.063 + 0.147 + 0.063 + 0.027

      = 0.657

(c) P(exactly one of the next three inspected passes) = P(pqq or qpq or qqp)

                 =  (0.7 × 0.3 × 0.3) + (0.3 × 0.7 × 0.3) + (0.3 × 0.3 × 0.7)

                 = 0.063 + 0.063 + 0.063

                 = 0.189

(d) P(at most one of the next three vehicles inspected passes) = P(pqq or qpq or qqp or qqq)

                 =  (0.7 × 0.3 × 0.3) + (0.3 × 0.7 × 0.3) + (0.3 × 0.3 × 0.7) + (0.3 × 0.3 × 0.3)

                 = 0.063 + 0.063 + 0.063 + 0.027

                 = 0.216

(e) Given that at least one of the next 3 vehicles passes inspection, what is the probability that all 3 pass (a conditional probability)?

P(at least one of the next three vehicles inspected passes) = P(ppp or ppq or pqp or qpp or pqq or qpq or qqp)

=  (0.7 × 0.7 × 0.7) + (0.7 × 0.7 × 0.3) + (0.7 × 0.3 × 0.7) + (0.3 × 0.7 × 0.7) + (0.7 × 0.3 × 0.3) + (0.3 × 0.7 × 0.3) + (0.3 × 0.3 × 0.7)

= 0.343 + 0.147 + 0.147 + 0.147 + 0.063 + 0.063 + 0.063

                  = 0.973  

With the condition that at least one of the next 3 vehicles passes inspection, the probability that all 3 pass is,

                         = \frac{P(all\ of\ the\ next\ three\ vehicles\ inspected\ pass)}{P(at\ least\ one\ of\ the\ next\ three\ vehicles\ inspected\ passes)}

                         = \frac{0.343}{0.973}

                         = 0.353

3 0
4 years ago
Read 2 more answers
Trigonometry need help on this one
morpeh [17]

Answer:

Step-by-step explanation:

you have a right triangle, more precisely is a isosceles right triangle, as you have one angle= 45⁰, the other angle is also= 45⁰

In this triangle the hypotenuse, c, is

c=9\sqrt{2}= 12.72

7 0
3 years ago
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