Question

A mine elevator was at a depth of -120 feet. After 15 seconds, the mine elevator was at a depth of -30 feet. What expression can be represented how to find the speed of the mine elevator in feet per second?

Answer 1

Answer:

The answers to the given question are:

i.  The equipment elevator is at a depth of 176 feet (-176 feet), while the miner's elevator is at a depth of 210 feet (-210 feet) below the surface.

ii. The miner's elevator is deeper than that of the equipment.

The speed of an object is the rate at which the object moves.

i.e. speed =

Thus,

Speed of the equipment elevator = 4 feet per second

Speed of the miner's elevator = 15 feet per second.

Time of descent of the equipment elevator = 30 + 14

                                 = 44 seconds

So that, the distance of the elevator at this time is;

speed =

⇒ distance = speed x time

                  = 4 x 44

                  = 176

  distance = - 176 feet

The distance of the miner's elevator after 14 seconds is:

speed =

⇒ distance = speed x time

                 = 15 x 14

                 = 210

 distance = - 210 feet

Thus, after another 14 seconds, the equipment elevator is at a depth of 176 feet (-176 feet), while the miner's elevator is at a depth of 210 feet (-210 feet) below the surface.

Therefore, the miner's elevator is deeper than that of the equipment.

Step-by-step explanation:

done