Answer:
20 but I am not sure.....
Answer:
b = 7, c = -44
Step-by-step explanation:
If the quadratic equation has the solutions -11 and 4, the two factors are:
Since when we use the zero factor property we get
x+11=0 ⇒ x= -11
x-4=0 ⇒ x=4
Thus, we have used the zero factor property in reverse to find the factorization of the quadratic equation.
Now we develop the multiplications between parenthesis:
So b is the number that accompanies the x: b = 7
and c is the independent number: c = -44
Hello from MrBillDoesMath!
Answer:
x = 19, y = 36
Discussion:
x + 3 = 22 (*)
2x - y = 2 (**)
Subtract 3 from both sides of (*)
x + 3 -3 = 22 = 3 = 19 =>
x = 19
Substitute x= 19 in (**)
2(19) - y = 2 =>
38 - y = 2 => (add y to both sides)
38 -y + y = 2 + y =>
38 = 2 + y => (subtract 2 from both sides)
38 -2 = 2 -2 + y =>
36 = y
Regards,
MrB
P.S. I'll be on vacation from Friday, Dec 22 to Jan 2, 2019. Have a Great New Year!
The cross product of the normal vectors of two planes result in a vector parallel to the line of intersection of the two planes.
Corresponding normal vectors of the planes are
<5,-1,-6> and <1,1,1>
We calculate the cross product as a determinant of (i,j,k) and the normal products
i j k
5 -1 -6
1 1 1
=(-1*1-(-6)*1)i -(5*1-(-6)1)j+(5*1-(-1*1))k
=5i-11j+6k
=<5,-11,6>
Check orthogonality with normal vectors using scalar products
(should equal zero if orthogonal)
<5,-11,6>.<5,-1,-6>=25+11-36=0
<5,-11,6>.<1,1,1>=5-11+6=0
Therefore <5,-11,6> is a vector parallel to the line of intersection of the two given planes.
