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DedPeter [7]
1 year ago
5

) Find the value of x. 3 A) 9 B) 10 C) 11 D) 12

Mathematics
1 answer:
valentinak56 [21]1 year ago
7 0

The answer is 12

because

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89 points

Step-by-step explanation:

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3 years ago
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Find the zeros of polynomial function and solve polynomials equations.<br> f(x)=24x^3-64x^2-21x+56
8090 [49]

Since this polynomial has 4 terms, factoring by grouping should be the first thing we try here.

So, we have:

8x^2(3x-8)-7(3x-8)=0 \implies\\ (8x^2-7)(3x-8)=0

So, we can use ZPP to find out roots:

3x-8 =0 \implies\\ x=\frac{8}{3}\\ 8x^2-7=0 \implies \\ 8x^2=7 \implies \\ x^2=\frac{7}{8} \implies \\ x=\pm\frac{\sqrt{7}}{\sqrt{{8}}}\\ \text{Rationalizing denominator:}\\ x=\pm\frac{\sqrt{56}}{8}

So our three roots are:

x \in \{\frac{8}{3},\frac{\sqrt{56}}{8},-\frac{\sqrt{56}}{8}\}

8 0
2 years ago
What is the answer?! Pls help!
Levart [38]
If u divide the area by length then u will get the width as x+4
7 0
3 years ago
Solve for W when: B = 703 * w/h (squared). Note: w/h is a fraction where h is squared
svlad2 [7]
We are given with the expression <span> B = 703 * w / h^2. To isolate w in the function, we multiply the whole equation by h^2. This results to B h^2 = 703 w. Next, we divide the equation by 703 to isolate w. The final expression of w becomes w = B h^2 / 703  </span>
3 0
3 years ago
A new restaurant is to contain​ two-seat tables and​ four-seat tables. Fire codes limit the​ restaurant's maximum occupancy to 7
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Let t and f be the number to two and four seat tables respectively.

t+f=22, solve for t

t=22-f, then we are told that capacity must be less than or equal to 72 people.

2t+4f≤72, using t found above in this equation we get:

2(22-f)+4f≤72 perform indicated multiplication on left side

44-2f+4f≤72  combine like terms on left side

44+2f≤72  subtract 44 from both sides

2f≤28  divide both sides by 2

f≤14  Since f=integer

f=14, and since t=22-f

t=8

So they should purchase 14 four seat tables and 8 two seat tables.
3 0
3 years ago
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