Answer: 12 inches
Step-by-step explanation: In this problem, since we're asked to find the length of the median, let's use our formula for the area of a trapezoid that involves the median which is shown below.
Area = median · height
We know that the area is 144 and the height is 9 so we can set up the equation 144 = M · 12. Now to solve for <em>m</em>, we divide both sides of the equation by 12 and we find that 12 = M.
So the length of the median of the trapezoid is 12 inches.
Add 10 to 894.
894 + 10 = 904
Anna's balance after writing check #1620 was B) $1606.42
Step-by-step explanation:
Step 1; Whenever you make a payment, make a cash withdrawal the money in your account decreases as you're giving your money to someone else. So the money spent or taken is reduced from the balance in your account.
Whenever you get your paycheck or make a deposit the money you have in your account increases. So the amount of money put in or the money you are paid is added with the balance you have in your account.
Step 2; Anna had a balance of $2,339.27 before writing the check #1620. She withdraws an amount of $732.85 under the description of the city bank. As she withdrew money, withdrawn money is subtracted from the balance.
Balance after writing the #1620 check = Balance before writing the #1620 check - amount of money withdrawn = $2,339.27 - $732.85 = $1,606.42,
So her balance after writing check #1620 was $1,606.42.
Check the picture below.
where is the -16t² coming from? that's Earth's gravity pull in feet.
![\bf ~~~~~~\textit{initial velocity} \\\\ \begin{array}{llll} ~~~~~~\textit{in feet} \\\\ h(t) = -16t^2+v_ot+h_o \end{array} \quad \begin{cases} v_o=\stackrel{30}{\textit{initial velocity of the object}}\\\\ h_o=\stackrel{6}{\textit{initial height of the object}}\\\\ h=\stackrel{}{\textit{height of the object at "t" seconds}} \end{cases} \\\\\\ h(t)=-16t^2+30t+6 \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=%5Cbf%20~~~~~~%5Ctextit%7Binitial%20velocity%7D%20%5C%5C%5C%5C%20%5Cbegin%7Barray%7D%7Bllll%7D%20~~~~~~%5Ctextit%7Bin%20feet%7D%20%5C%5C%5C%5C%20h%28t%29%20%3D%20-16t%5E2%2Bv_ot%2Bh_o%20%5Cend%7Barray%7D%20%5Cquad%20%5Cbegin%7Bcases%7D%20v_o%3D%5Cstackrel%7B30%7D%7B%5Ctextit%7Binitial%20velocity%20of%20the%20object%7D%7D%5C%5C%5C%5C%20h_o%3D%5Cstackrel%7B6%7D%7B%5Ctextit%7Binitial%20height%20of%20the%20object%7D%7D%5C%5C%5C%5C%20h%3D%5Cstackrel%7B%7D%7B%5Ctextit%7Bheight%20of%20the%20object%20at%20%22t%22%20seconds%7D%7D%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5C%5C%20h%28t%29%3D-16t%5E2%2B30t%2B6%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)
![\bf \left(-\cfrac{30}{2(-16)}~~,~~6-\cfrac{30^2}{4(-16)} \right)\implies \left( \cfrac{30}{32}~,~6+\cfrac{225}{16} \right)\implies \left(\cfrac{15}{16}~,~\cfrac{321}{16} \right) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill (\stackrel{\stackrel{\textit{how many}}{\textit{seconds it took}}}{0.9375}~~,~~\stackrel{\stackrel{\textit{how many feet}}{\textit{up it went}}}{20.0625})~\hfill](https://tex.z-dn.net/?f=%5Cbf%20%5Cleft%28-%5Ccfrac%7B30%7D%7B2%28-16%29%7D~~%2C~~6-%5Ccfrac%7B30%5E2%7D%7B4%28-16%29%7D%20%5Cright%29%5Cimplies%20%5Cleft%28%20%5Ccfrac%7B30%7D%7B32%7D~%2C~6%2B%5Ccfrac%7B225%7D%7B16%7D%20%5Cright%29%5Cimplies%20%5Cleft%28%5Ccfrac%7B15%7D%7B16%7D~%2C~%5Ccfrac%7B321%7D%7B16%7D%20%5Cright%29%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%20~%5Chfill%20%28%5Cstackrel%7B%5Cstackrel%7B%5Ctextit%7Bhow%20many%7D%7D%7B%5Ctextit%7Bseconds%20it%20took%7D%7D%7D%7B0.9375%7D~~%2C~~%5Cstackrel%7B%5Cstackrel%7B%5Ctextit%7Bhow%20many%20feet%7D%7D%7B%5Ctextit%7Bup%20it%20went%7D%7D%7D%7B20.0625%7D%29~%5Chfill)
