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2 years ago

5

Any help on this image please? i don't get it

1 answer:

Stella [2.4K]2 years ago

8 0

Step-by-step explanation:

hope you can understand

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PLEASEEEE HELPPP!!!!

Serggg [28]

Answer:

A.

Step-by-step explanation:

5 0

2 years ago

2(x-3)-8< -4 I need a explanation and the answer please.

tresset_1 [31]

Answer:

The solution to the inequality is:

$x$

The number line solution graph is also attached below.

Step-by-step explanation:

Given the inequality

$2(x-3)-8< -4$

Add 8 to both sides

$2\left(x-3\right)-8+8$

$2\left(x-3\right)$

Divide both sides by 2

$\frac{2\left(x-3\right)}{2}$

$x-3$

Add 3 to both sides

$x-3+3$

$x$

Thus, the solution to the inequality is:

$x$

The number line solution graph is also attached below.

6 0

2 years ago

Jaclyn is selling cookies for her club. She sells 2 boxes for $5. What unit rate expresses the cost per box?

Amiraneli [1.4K]

Divide 5 by 2 representing each box by the price. Which equals to $2.50 each box.

8 0

2 years ago

The projected rate of increase in enrollment at a new branch of the UT-system is estimated by E ′ (t) = 12000(t + 9)−3/2 where E

nexus9112 [7]

Answer:

The projected enrollment is $\lim_{t \to \infty} E(t)=10,000$

Step-by-step explanation:

Consider the provided projected rate.

$E'(t) = 12000(t + 9)^{\frac{-3}{2}}$

Integrate the above function.

$E(t) =\int 12000(t + 9)^{\frac{-3}{2}}dt$

$E(t) =-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+c$

The initial enrollment is 2000, that means at t=0 the value of E(t)=2000.

$2000=-\frac{24000}{\left(0+9\right)^{\frac{1}{2}}}+c$

$2000=-\frac{24000}{3}+c$

$2000=-8000+c$

$c=10,000$

Therefore, $E(t) =-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+10,000$

Now we need to find $\lim_{t \to \infty} E(t)$

$\lim_{t \to \infty} E(t)=-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+10,000$

$\lim_{t \to \infty} E(t)=10,000$

Hence, the projected enrollment is $\lim_{t \to \infty} E(t)=10,000$

8 0

2 years ago

What would the equation be of the relationship??

Brums [2.3K]

I don’t really know that

6 0

3 years ago