Question

Type the correct answer in the box. express your answer to two significant figures. a reaction between 1.7 moles of zinc iodide and excess sodium carbonate yields 12.6 grams of zinc carbonate. this is the equation for the reaction: na2co3 zni2 → 2nai znco3. what is the percent yield of zinc carbonate? the percent yield of zinc carbonate is %.

Answer 1

The percent yield of zinc carbonate is 5.91%.

What is chemical reaction?

The chemical reaction is the reaction between two reactants which led to the formation of products.

The products are substances which forms after reaction. The reactants are the substances which are original materials.

Given is a reaction between 1.7 moles of zinc iodide and excess sodium carbonate yields 12.6 grams of zinc carbonate.

The given balanced equation is:  Na₂CO₃ + ZnI₂ → 2NaI + ZnCO₃

From given moles of zinc iodide, the moles of zinc carbonate

1.7 moles of ZnI₂ = 1.7 moles of ZnCO₃

Molar mass of zinc carbonate is 125.38 g/mol

Theoretical yield =  1.7 moles of ZnCO₃ x  125.38 g/mol = 213.15 g  ZnCO₃

Theoretical yield is 213.15 g and the actual yield is given as 12.6 g.

percent yield = [ 12.6 g / 213.15 g  ZnCO₃ ] x 100

percent yield = 5.91%

The percent yield of zinc carbonate is 5.91%.

Learn more about chemical reaction.

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