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Rus_ich [418]
2 years ago
9

3a: complete the table with values for x and y that makes this equation true 3x+y=15

Mathematics
1 answer:
Gnesinka [82]2 years ago
8 0

Answer:

  a. see the attachment for the table (also reproduced below)

  b. slope = -3; see the attachment for a graph

Step-by-step explanation:

A table of values for the function can be filled a couple of ways. One way is to draw the graph of the equation, and read the point values from it. Another way is to solve for each of the variables, and use those equations to find the missing table values.

__

<h3>a.</h3>

Solving the equation for y, we get ...

  3x +y = 15

  y = -3x +15 . . . . . . subtract 3x; this is "point-slope form"

For the purpose of evaluating for different values of x, we can rearrange this a bit to ...

  y = 3(5 -x) . . . . factor out 3

The given table has x-values of 0, 2, 3, 6. The corresponding y-values are ...

  y = 3(5 -{0, 2, 3, 6}) = 3{5, 3, 2, -1} = {15, 9, 6, -3} . . . . for x={0, 2, 3, 6}

Solving the equation for x, we get ...

  y/3 = 5 -x . . . . . divide the above equation by 3

  x = 5 -(y/3) . . . . . add x-(y/3)

For y-values {0, 3, 8}, the corresponding x-values are ...

  x = 5 -{0, 3, 8}/3 = 5 -{0, 1, 8/3} = {5, 4, 7/3} . . . . for y={0, 3, 8}

Then our table of values is ...

  \begin{array}{|c|c|c|c|c|c|c|c|}\cline{1-8}x&2&4&6&0&3&5&7/3\\y&9&3&-3&15&6&0&8\\\cline{1-8}\end{array}

__

<h3>b.</h3>

The points in the above table can be plotted, and the line drawn through them. Sometimes using the points that are farthest apart makes this easier: (0, 15) and (6, -3).

slope

When we solved for y, we had the equation in <em>slope-intercept form</em>. The slope is the x-coefficient in that equation:

  y = -3x +15   ⇒   slope = -3

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As per the concept of normal distribution, the two diameters of the bolt that has separate the top 3% and the bottom 3% are 5.2836 mm and 5.0764 mm respectively .

Normal distribution:

Normal distribution means the probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean and it has the bell shaped curve.

Given,

The diameters of bolts produced in a machine shop are normally distributed with a mean of 5.18 millimeters and a standard deviation of 0.07 millimeters.

Here we need to find the two diameters that separate the top 3% and the bottom 3% and these diameters could serve as limits used to identify which bolts should be rejected. we have also round off the result into nearest hundredth.

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Next we have to take P(X < x₂) = 3% when we convert it into decimal then we get P (X < x₂) = 0.03

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