Theo's friend made a display with dimensions that were each half as long as those theo used. what is the approximate mass of the
1 answer:
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(_/18+2_/3)^(2
=(3_/2^(2 + (2)(2_/3)(3_/2) + 2_/3^(2)
=18+ 12_/6 +12
=30+12_/6
hope this helps
=(3_/2^(2 + (2)(2_/3)(3_/2) + 2_/3^(2)
=18+ 12_/6 +12
=30+12_/6
hope this helps
Answer:
Step-by-step explanation:
Use the Pythagorean theorem.
a and b are the two side lengths
c is the hypotenuse (value across from the right angle)
Plug in the values that you are given.
Solve for x
x=