What is it anyone answer it now
Answer:
a) 1.3 rad/s
b) 0.722 s
Explanation:
Given
Initial velocity, ω = 0 rad/s
Angular acceleration of the wheel, α = 1.8 rad/s²
using equations of angular motion, we have
θ2 - θ1 = ω(0)[t2 - t1] + 1/2α(t2 - t1)²
where
θ2 - θ1 = 53.2 rad
t2 - t1 = 7s
substituting these in the equation, we have
θ2 - θ1 = ω(0)[t2 - t1] + 1/2α(t2 - t1)²
53.2 =ω(0) * 7 + 1/2 * 1.8 * 7²
53.2 = 7.ω(0) + 1/2 * 1.8 * 49
53.2 = 7.ω(0) + 44.1
7.ω(0) = 53.2 - 44.1
ω(0) = 9.1 / 7
ω(0) = 1.3 rad/s
Using another of the equations of angular motion, we have
ω(0) = ω(i) + α*t1
1.3 = 0 + 1.8 * t1
1.3 = 1.8 * t1
t1 = 1.3/1.8
t1 = 0.722 s
Answer:
A nugget. It sounds weird I know, but thats the answer.
on the opposite side
Answer: Option B.
<u>Explanation:</u>
Since the pulse is sent down through a rope which is tied to a wall means that the end of the pulse is fixed and it is not loose. If the pulse is reflected at a fixed end, the pulse will reflect off that end which is fixed and the if the end does not move.
This means that if the pulse which has an upward displacement will reflect off the end if the end is fixed like a wall and will return with a downward displacement.