Answer:
Answer:
safe speed for the larger radius track u= √2 v
Explanation:
The sum of the forces on either side is the same, the only difference is the radius of curvature and speed.
Also given that r_1= smaller radius
r_2= larger radius curve
r_2= 2r_1..............i
let u be the speed of larger radius curve
now, \sum F = \frac{mv^2}{r_1} =\frac{mu^2}{r_2}∑F=
r
1
mv
2
=
r
2
mu
2
................ii
form i and ii we can write
v^2= \frac{1}{2} u^2v
2
=
2
1
u
2
⇒u= √2 v
therefore, safe speed for the larger radius track u= √2 v
Answer:
The correct answers are It is the resistance of an object to changes in its motion, and It is a force
Answer:
Explanation:
As we know that the small particle is in equilibrium at an angle of 16 degree with the vertical
so here we can use force balance in vertical and horizontal direction
now from above equation we have
also by division of above two equations we have
now from above equation again
Explanation:
potential difference = current × risstance
see part a point3 current is same
v= IR
v = 8×0.2
v= 1.6
see part a point 5
this potential difference is less than cell
