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ivann1987 [24]
1 year ago
7

Question 7 of 10

Mathematics
1 answer:
sergejj [24]1 year ago
6 0

The product that is  undefined is known a CD, where C is a 3 x 1 matrix and D is a 1 x 2 matrix.

<h3>What is the matrix about?</h3>

Looking at the product of matrix, note that to multiply  the two matrix, the column of the first matrix needs to have the same or equal to the row of the 2nd matrix.

And in this case (propensity), it is not satisfied by the first  option because:

C =  3 x 1  and

O= 2 x 1  matrix

In this case CD is therefore undefined.

So we can say that The product that is  undefined is known a CD, where C is a 3 x 1 matrix and D is a 1 x 2 matrix.

Learn more about matrix from

brainly.com/question/94574

#SPJ1

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Read 2 more answers
Let f(x) = (5)^x+1 .Evaluate f (-3) without using a calculator
rewona [7]

Answer:

f\left(-3\right)=\frac{126}{125}

Step-by-step explanation:

Given

f\left(x\right)\:=\:\left(5\right)^x+1

Putting x = -3 to find f(-3)

f\left(-3\right)\:=\:\left(5\right)^{\left(-3\right)}+1

as

5^{-3}=\frac{1}{125}       ∵  \mathrm{Apply\:exponent\:rule}:\quad \:a^{-b}=\frac{1}{a^b}

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f\left(-3\right)=\frac{1}{125}+1

\mathrm{Convert\:element\:to\:fraction}:\quad \:1=\frac{1\cdot \:125}{125}

f\left(-3\right)=\frac{1\cdot \:\:125}{125}+\frac{1}{125}

\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}

f\left(-3\right)=\frac{1\cdot \:\:125+1}{125}

f\left(-3\right)=\frac{126}{125}      ∵ 1\cdot \:125+1=126

Thus,

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6 0
3 years ago
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