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zubka84 [21]
2 years ago
10

Find a formula for cos(tan−1(2x)) in terms of x

Mathematics
1 answer:
aleksklad [387]2 years ago
4 0

~\cos\left( \tan^{-1} 2x\right)\\\\\\=\cos \left[\cos^{-1} \dfrac{1}{\sqrt{(2x)^2+1^2}} \right]~~~~~~~~~~~~~~~~~~~~~~~~~~;[\text{Pythagorean theorem}]\\\\\\=\cos \left( \cos^{-1} \dfrac{1}{\sqrt{4x^2 +1}} \right)\\\\\\=\dfrac{1}{\sqrt{4x^2 +1}}

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