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Margaret [11]
2 years ago
6

Pls help me to find the answer e,f,g,h no. only

Mathematics
1 answer:
Nikitich [7]2 years ago
6 0

1. Change both numbers to common base.

2. Use quotient rule a^x \div a^y = a^{x-y}

e)

You can write 9 as 3², then both numbers have the same base.

9^x = (3^2)^x = 3^{2x}, where x is the exponent

I cannot really see the exponents because picture is bad quality.

9^x \div 3^y =

= (3^2)^x \div 3^y =

=3^{2x} \div 3^y =

= 3^{2x-y}

You want to replace x and y with actual numbers, but as I said the picture is too bad.

f)

Convert to base 4, then quotient rule.

g)

Use the quotient rule, you already have same base.

h)

Convert to base \frac{2}{3}, then quotient rule.

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You are remodeling your kitchen. You've contacted two tiling companies who
ICE Princess25 [194]

Answer:

12x=10(25+x)

Step-by-step explanation:

Jim's rate=x

Pete's rate=y

Jim and Pete lays the same number of tiles.

So we have,

12x=10y

Pete's can lay 25 more tiles than Jim per hour

We have

y=25+x

Substitute y=25+x into 12x=10y

12x=10y

12x=10(25+x)

12x=250+10x

12x-10x=250

2x=250

x=250/2

=125

x=125

12x=10(25+x) is the equation used to find the rate that Jim can lay tiles

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3 years ago
Write the phrase as an expression.<br> The product of 25 and 6
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What is the answer of Three over <br> Four multiply to eight over nine ?
andrew11 [14]
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5 0
4 years ago
Read 2 more answers
Solve the following problems : Given: S, T, and U are the midpoints of RP , PQ , and QR respectively. Prove: △SPT≅△UTQ.
AleksandrR [38]

Answer:

Hence Proved △ SPT ≅ △ UTQ

Step-by-step explanation:

Given: S, T, and U are the midpoints of Segment RP , segment PQ , and segment QR respectively of Δ PQR.

To prove: △ SPT ≅ △ UTQ

Proof:

∵ T is is the midpoint of PQ.

Hence PT = PQ    ⇒equation 1

Now,Midpoint theorem is given below;

The Midpoint Theorem states that the segment joining two sides of a triangle at the midpoints of those sides is parallel to the third side and is half the length of the third side.

By, Midpoint theorem;

TS║QR

Also, TS = \frac{1}{2} QR

Hence, TS = QU (U is the midpoint QR) ⇒ equation 2

Also by Midpoint theorem;

TU║PR

Also, TU = \frac{1}{2} PR

Hence, TU = PS (S is the midpoint QR) ⇒ equation 3

Now in △SPT and △UTQ.

PT = PQ (from equation 1)

TS = QU (from equation 2)

PS = TU (from equation 3)

By S.S.S Congruence Property,

△ SPT ≅ △ UTQ ...... Hence Proved

6 0
3 years ago
A sprinkler rotates 360 degrees the total are watered is 204yds squared<br> what is the raduius
SIZIF [17.4K]

The radius of the area the sprinkler has watered is 8.06 yards.

<h3>What is Rotation ?</h3>

Rotation is spinning around a fixed point with a fixed radius in circular motions.

It is given that a sprinkler rotates 360 degree

The area watered is 204 sq. yards

Radius = ?

A sprinkler rotates in circle

Therefore the area of the circle = π r²

204 = π r²

204 * 7 /22 = r²

r² = 64.91

r = 8.06 yards

Therefore the radius of the area the sprinkler has watered is 8.06 yards.

To know more about Rotation

brainly.com/question/1571997

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4 0
2 years ago
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