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Margaret [11]
2 years ago
6

Pls help me to find the answer e,f,g,h no. only

Mathematics
1 answer:
Nikitich [7]2 years ago
6 0

1. Change both numbers to common base.

2. Use quotient rule a^x \div a^y = a^{x-y}

e)

You can write 9 as 3², then both numbers have the same base.

9^x = (3^2)^x = 3^{2x}, where x is the exponent

I cannot really see the exponents because picture is bad quality.

9^x \div 3^y =

= (3^2)^x \div 3^y =

=3^{2x} \div 3^y =

= 3^{2x-y}

You want to replace x and y with actual numbers, but as I said the picture is too bad.

f)

Convert to base 4, then quotient rule.

g)

Use the quotient rule, you already have same base.

h)

Convert to base \frac{2}{3}, then quotient rule.

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Which equation demonstrates the associative property of multiplication
kherson [118]

Answer:

from what I remember ide say A

3 0
3 years ago
Given that cot θ = 1/√5, what is the value of (sec²θ - cosec²θ)/(sec²θ + cosec²θ) ?
Bogdan [553]

Step-by-step explanation:

\mathsf{Given :\;\dfrac{{sec}^2\theta - co{sec}^2\theta}{{sec}^2\theta + co{sec}^2\theta}}

\bigstar\;\;\textsf{We know that : \large\boxed{\mathsf{{sec}\theta = \dfrac{1}{cos\theta}}}}

\bigstar\;\;\textsf{We know that : \large\boxed{\mathsf{co{sec}\theta = \dfrac{1}{sin\theta}}}}

\mathsf{\implies \dfrac{\dfrac{1}{cos^2\theta} - \dfrac{1}{sin^2\theta}}{\dfrac{1}{cos^2\theta} + \dfrac{1}{sin^2\theta}}}

\mathsf{\implies \dfrac{\dfrac{sin^2\theta - cos^2\theta}{sin^2\theta.cos^2\theta}}{\dfrac{sin^2\theta + cos^2\theta}{sin^2\theta.cos^2\theta}}}

\mathsf{\implies \dfrac{sin^2\theta - cos^2\theta}{sin^2\theta + cos^2\theta}}

Taking sin²θ common in both numerator & denominator, We get :

\mathsf{\implies \dfrac{sin^2\theta\left(1 - \dfrac{cos^2\theta}{sin^2\theta}\right)}{sin^2\theta\left(1 + \dfrac{cos^2\theta}{sin^2\theta}\right)}}

\bigstar\;\;\textsf{We know that : \large\boxed{\mathsf{cot\theta = \dfrac{cos\theta}{sin\theta}}}}

\mathsf{\implies \dfrac{1 -cot^2\theta}{1 + cot^2\theta}}

\mathsf{Given :\;cot\theta = \dfrac{1}{\sqrt{5}}}

\mathsf{\implies \dfrac{1 - \left(\dfrac{1}{\sqrt{5}}\right)^2}{1 + \left(\dfrac{1}{\sqrt{5}}\right)^2}}

\mathsf{\implies \dfrac{1 - \dfrac{1}{5}}{1 + \dfrac{1}{5}}}

\mathsf{\implies \dfrac{\dfrac{5 - 1}{5}}{\dfrac{5 + 1}{5}}}

\mathsf{\implies \dfrac{5 - 1}{5 + 1}}

\mathsf{\implies \dfrac{4}{6}}

\mathsf{\implies \dfrac{2}{3}}

<u>Hence</u><u>,</u><u> option</u><u> </u><u>(</u><u>a)</u><u> </u><u>2</u><u>/</u><u>3</u><u> </u><u>is </u><u>your</u><u> </u><u>correct</u><u> </u><u>answer</u><u>.</u>

3 0
2 years ago
Which number results in a true sentence in 0.475 < ______ ? a.) 0.473 c.) 0.475 b.) 0.474 d.) 0.476
patriot [66]

Answer:

D.) 0.476

Step-by-step explanation:

The < sign means 'less than'. The only thing that .475 is less than is .476

7 0
2 years ago
The volume of the shape below is 6 square units. Determine the volume of the shape in two different ways.
REY [17]

The volume of the shape is 6 cubic units

<h3>How to determine the volume of the shape?</h3>

<u>Method 1</u>

From the figure, we can see that:

  • There are 6 cubes in the figure
  • The dimensions of the cubes are equal
  • The volume of each cube is 1 cubic unit

So, the volume of the shape is

Volume = Number of cubes * Volume of each cube

Substitute the known values in the above equation

Volume = 6 * 1

Evaluate

Volume = 6

<u>Method 2</u>

From the figure, we can see that:

  • There are 6 cubes in the figure
  • 2 cubes at the top and 4 at the bottom
  • The dimensions of the cubes are equal
  • The volume of each cube is 1 cubic unit

So, the volume of the shape is

Volume = Top cubes +  Bottom cubes

This gives

Volume = 2 * Volume of each cube + 4 * Volume of each cube

Substitute the known values in the above equation

Volume = 2 * 1 + 4 * 1

Evaluate

Volume = 6

Hence, the volume of the shape is 6 cubic units

Read more about volumes at:

brainly.com/question/1972490

#SPJ1

5 0
1 year ago
PLS HELP ME I ADDED MORE POINTS
ZanzabumX [31]

Answer: D. (-6,2)

Step-by-step explanation:

y = x + 8  

2x + y = -10

v

2x + x +8 = -10

x = -6

y = -6 + 8     ( plug in x (-6) )

y = 2

( x, y) = ( -6, 2)

4 0
2 years ago
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