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natka813 [3]
2 years ago
9

Which equation justifies why seven to the one third power equals the cube root of seven?

Mathematics
1 answer:
Rudiy272 years ago
4 0

The equation that  justifies why seven to the one third power equals the cube root of seven is seven to the one third power all raised to the third power equals seven to the one third times three power equals seven

<h3>How to solve an equation?</h3>

using indices law,

\sqrt[n]{x}  = x^{1 / n}

Therefore, let's justify

7^{1/3}  = \sqrt[3]{7}

Hence, the justification is as follows;

(7^{1 /3}) ^{3} =(7^{1/3})^{3}  = 7

Therefore, the justification of is that seven to the one third power all raised to the third power equals seven to the one third times three power equals seven

learn more on equation here: brainly.com/question/13426221

#SPJ1

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If 2 f left parenthesis x right parenthesis plus f left parenthesis 1 minus x right parenthesis equals x squared2f(x)+f(1 − x)=x
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The correct result would be f(x) = x^2 / 2 - f(1-x) / 2.
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