Question

Solve the discriminant

Answer 1

Answer:

a

Step-by-step explanation:

given a quadratic equation in standard form

ax² + bx + c = 0 ( a ≠ 0 )

then the discriminant

Δ = b² - 4ac

• if b² - 4ac > 0 then 2 real solutions

• if b² - 4ac = 0 then 2 real and equal solutions

• if b² - 4ac < 0 then no real solutions

given

$\frac{3}{4}$ x² - 3x = - 4 ( add 4 to both sides )

$\frac{3}{4}$ x² - 3x + 4 = 0 ← in standard form

with a = $\frac{3}{4}$ b = - 3 , c = 4

then

b² - 4ac = (- 3)² - ( 4 × $\frac{3}{4}$ × 4) = 9 - 12 = - 3

since b² - 4ac < 0 then equation has no real solutions