1234.5 x10 = 12345
12.345 / 100 = 0.12345
Answer:
1.256g = 1,256,000 micrograms
1.256g = 1256mg
1.256g = 0,001256kg
Step-by-step explanation:
This is a conversion of units problem, that can be solved by rules of three.
In a rule of three problem, the first step is identifying the measures and how they are related, if their relationship is direct of inverse.
When the relationship between the measures is direct, as the value of one measure increases, the value of the other measure is going to increase too.
When the relationship between the measures is inverse, as the value of one measure increases, the value of the other measure will decrease.
Unit conversion problems, like this one, is an example of a direct relationship between measures.
First step: 1.256g to micrograms
Each g has 1,000,000 ug. So:
1g - 1,000,000 ug
1.256g - xug
x = 1,000,000*1.256
x = 1,256,000 micrograms
Second step: 1.256g to mg
Each g has 1,000 mg. So:
1g - 1,000mg
1.256g - xmg
x = 1,000*1.256
x = 1256mg
Final step: 1.256g to kg
Each kg has 1,000g. So:
1kg - 1,000g
xkg - 1.256g
1,000x = 1.256
x = 0,001256kg
I'm going to go with C.
The inequality isn't greater than OR EQUAL TO which marks out B and D.
The inequality is showing that it is greater than -21 meaning that the shaded area should be towards the positive which in turn marks out A.
Answer:
Step-by-step explanation:
From the information given,
Number of personnel sampled, n = 85
Mean or average = 6.5
Standard deviation of the sample = 1.7
We want to determine the confidence interval for the mean number of years that personnel spent in a particular job before being promoted.
For a 95% confidence interval, the confidence level is 1.96. This is the z value and it is determined from the normal distribution table. We will apply the following formula to determine the confidence interval.
z×standard deviation/√n
= 1.96 × 6.5/√85
= 1.38
The confidence interval for the mean number of years spent before promotion is
The lower end of the interval is 6.5 - 1.38 = 5.12 years
The upper end is 6.5 + 1.38 = 7.88 years
Therefore, with 95% confidence interval, the mean number of years spent before being promoted is between 5.12 years and 7.88 years