Since the reflected figure is moved to the third quardrant, the reflection should be across the x-axis.
Also, if we compare the width and height of the orginial triangle with that of the reflected one, it is clear that it is dilated with a scale factor of 0.25.
Answer:
5a. ΔGKM ~ ΔSPM by SAS
b. ΔABC is not similar to ΔDEF
6. The missing side is 2
Step-by-step explanation:
5a. Yes, the triangles are similar.
<KMG ≅ <PMS (vertically opposite angles)
ΔGKM ~ ΔSPM by SAS
Ratio: GM:SM OR KM:PM
3:6 OR 2:4
1:2 OR 1:2
Ratio: 1:2
b. No, the triangles are not similar
ΔABC is not similar to ΔDEF
Ratio: AC:DF OR AB:DE
4:6 OR 2:4.5
1:1.5 ≠ 1:2.25
Ratio: not similar
6. let the missing side of the triangle be represented by x. Since the triangle is a right angled triangle, then applying the Pythagoras theorem we have;
=
+ 
=
+ 
144 =
+ 100
= 144 - 100
= 44
x = 
= 
= 2
x = 2
The missing side is 2
.
Simple. 1.66666667 x 3 = 5
Answer:
x>-1.25
Step-by-step explanation:
0.2x+4-3>-7-6.2x
0.2x+1>-7-6.2x
0.2x+6.2x>-7-1
6.4x>-8
x>-1.25
or x>-5/4,x>-1 1/4, xE(-1.25, infinite)
7x + 1
Combine like terms: 2x + 5x
Then add the remaining terms: 7x + 1