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Delicious77 [7]

1 year ago

14

Please help with this question

1 answer:

posledela1 year ago

5 0

B, the lowest because would you rather pay 12% daily or monthly

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Find the value of y...

soldier1979 [14.2K]

Answer:

y=0

Step-by-step explanation:

Rewrite Evaluate Powers:

3 $3^{2y-1}+3^{-1}+2*3^{y}*3^{-1}=1$

Calculate:

$(3^{y})^{2}*\frac{1}{3} +2*3^{y}*\frac{1}{3}=1$

Solve using substitution:

$(3^{y})^{2}*\frac{1}{3} +\frac{2}{3} *3^{y}=1$ $t=3^{y}$

Solve the equation for t:

$t^{2}*\frac{1}{3}+\frac{2}{3}t=1$

t=-3

t=1

Substitute back to t=3^y

3^y=-3

3^y=1

y∉R

$3^{y}=1$

y=0

5 0

2 years ago

A triangle with an area of 23 cm² is dilated by a factor of 6. What is the area of the dilated triangle? Enter your answer in th

Marizza181 [45]

Given that:
Area of triangle=23 cm²
Dilation factor= 6
It means that the area of the dilated triangle is 6²=36 times of the original.
Now area of dilated triangle, A'=36 x 23
A'= 828 cm²

Answer: Area of dilated triangle is 828 cm².

7 0

3 years ago

Read 2 more answers

Directions: Calculate the area of a circle using 3.14x the radius

Leokris [45]

$\qquad\qquad\huge\underline{{\sf Answer}}♨$

As we know ~

Area of the circle is :

$\qquad \sf \dashrightarrow \:\pi {r}^{2}$

And radius (r) = diameter (d) ÷ 2

[ radius of the circle = half the measure of diameter ]

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<h3>Problem 1</h3>

$\qquad \sf \dashrightarrow \:r = d \div 2$

$\qquad \sf \dashrightarrow \:r = 4.4\div 2$

$\qquad \sf \dashrightarrow \:r = 2.2 \: mm$

Now find the Area ~

$\qquad \sf \dashrightarrow \: \pi {r}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times {(2.2)}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times {4.84}^{}$

$\qquad \sf \dashrightarrow \:area \approx 15.2 \: \: mm {}^{2}$

・．━━━━━━━†━━━━━━━━━．・

<h3>problem 2</h3>

$\qquad \sf \dashrightarrow \:r = d \div 2$

$\qquad \sf \dashrightarrow \:r = 3.7 \div 2$

$\qquad \sf \dashrightarrow \:r = 1.85 \: \: cm$

Bow, calculate the Area ~

$\qquad \sf \dashrightarrow \: \pi {r}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times (1.85) {}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times 3.4225 {}^{}$

$\qquad \sf \dashrightarrow \:area \approx 10.75 \: \: cm {}^{2}$

・．━━━━━━━†━━━━━━━━━．・

<h3>Problem 3 </h3>

$\qquad \sf \dashrightarrow \:\pi {r}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times (8.3) {}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times 68.89$

$\qquad \sf \dashrightarrow \:area \approx216.31 \: \: cm {}^{2}$

・．━━━━━━━†━━━━━━━━━．・

<h3>Problem 4</h3>

$\qquad \sf \dashrightarrow \:r = d \div 2$

$\qquad \sf \dashrightarrow \:r = 5.8 \div 2$

$\qquad \sf \dashrightarrow \:r = 2.9 \: \: yd$

now, let's calculate area ~

$\qquad \sf \dashrightarrow \:3.14 \times {(2.9)}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times 8.41$

$\qquad \sf \dashrightarrow \:area \approx26.41 \: \: yd {}^{2}$

・．━━━━━━━†━━━━━━━━━．・

<h3>problem 5</h3>

$\qquad \sf \dashrightarrow \:r = d \div 2$

$\qquad \sf \dashrightarrow \:r = 1 \div 2$

$\qquad \sf \dashrightarrow \:r = 0.5 \: \: yd$

Now, let's calculate area ~

$\qquad \sf \dashrightarrow \:\pi {r}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times (0.5) {}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times 0.25$

$\qquad \sf \dashrightarrow \:area \approx0.785 \: \: yd {}^{2}$

・．━━━━━━━†━━━━━━━━━．・

<h3>problem 6</h3>

$\qquad \sf \dashrightarrow \:\pi {r}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times {(8)}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times 64$

$\qquad \sf \dashrightarrow \:area = 200.96 \: \: yd {}^{2}$

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8 0

2 years ago

What is the solution to this inequality?

AlladinOne [14]

Answer:

D

Step-by-step explanation:

The answer is D, because when you divide x by a negative the sign changes

7 0

2 years ago

lighting if a 25-foot-tall house cast a 75-foot shadow at the same time that a streetlight casts a 60-foot shadow how tall is th

jolli1 [7]

Answer:

The street light is 20 feet tall.

Step-by-step explanation:

This question depends on a proportion. Keep your height of the object in one ratio and the length of the shadow in the other.

25/x = 75/60 Notice the height of the structure is on the left. The length of the shadow is on the right. Cross multiply

75x = 60 * 25 Combine the right

75x = 1500 Divide by 75

x = 1500/75

x = 20

The street light is 20 feet tall.

3 0

2 years ago