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1 year ago

Please help with this question

Mathematics

1 answer:

posledela1 year ago

5 0

B, the lowest because would you rather pay 12% daily or monthly

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PLEASE HELP ASAP !!

wariber [46]

Answer:

First figure: $954cm^3$

Second figure: $1,508yd^3$

Third figure:

Height= q
Side length = r

Fourth figure:  $726cm^3$

Explanation:

A. First figure:

1. Formula:

$\text{Volume of a cylinder}=\pi \times radius^2\times length$

2. Data:

radius = 9cm / 2 = 4.5cm

length = 15 cm

3. Substitute in the formula and compute:

$Volume=\pi \times (4.5cm)^2\times (15cm)\approx 954cm^3\approx 954cm^3$

B. Second figure

1. Formula:

$\text{Volume of a leaned cylinder}=\pi \times radius^2\times height$

2. Data:

radius = 12yd

height = 40 yd

3. Substitute and compute:

$Volume=\pi \times (12yd)^2\times (40yd)\approx 1,507.96yd^3\approx 1,508yd^3$

C) Third figure

a) The height is the segment that goes vertically upward from the center of the base to the apex of the pyramid, i.e. q .

The apex is the point where the three leaned edges intersect each other.

b) The side length is the measure of the edge of the base, i.e. r .

When the base of the pyramid is a square the four edges of the base have the same side length.

D) Fourth figure

1. Formula

The volume of a square pyramide is one third the product of the area of the base (B) and the height H).

$Volume=(1/3)B\times H$

2. Data:

height: H = 18cm

side length of the base: 11 cm

3. Calculations

a) Calculate the area of the base.

The base is a square of side length equal to 11 cm:

$\text{Area of the base}=B=(11cm)^2=121cm^2$

b) Volume of the pyramid:

$Volume=(1/3)B\times H=(1/3)\times 121cm^2\times 18cm=726cm^3$

4 0

3 years ago

Read 2 more answers

the first term of an arithmetic sequence is 10 and the sum of the first five terms is 250,find the sequence

Crazy boy [7]

Answer:

The sequence is:

10, 30, 50, 70, 90.....................

Step-by-step explanation:

We have,

First term (a) = 10

Common difference (d) = ?

Sum of first 5 terms ( $S_{5}$ ) = 250

or, $\frac{n}{2} [{2a+(n-1)d}] = 250$

or, $\frac{5}{2} [2*10 + 4d]=250$

or, $\frac{5}{2} * 4[5+d]=250$

or, 10(5 + d) =250

or, 5 + d = 25

∴ d = 20

Now,

2nd term = a + d = 10 + 20 = 30

3rd term = a + 2d = 10 + 2*20 = 10 + 40 = 50

4th term = a + 3d = 10 + 3*20 = 10 + 60 = 70

5th term = a + 4d = 10 + 4*20 = 10 + 80 = 90

8 0

3 years ago

The height of males approximates a normal distribution. The average height of the players on an NBA team is 6.6 feet with a stan

lara [203]

D) 4.5 Standard Deviations Above the Mean

All you have to do is add .2 to 6.6 until you reach 7.5

6.8
7.0
7.2
7.4

Then you only need half of .2 to reach 7.5, so it's 4.5 standard deviations above the mean

6 0

2 years ago

Please answer this 1234rt5y6huj7ki

patriot [66]

Answer:

The answer would be option B.

Step-by-step explanation:

There are more people clustered in 22-25 years and the outlier is 38-41 years.

8 0

3 years ago

How could you rewrite 0.05 × 10 = 0.5 as a division equation ? explain how you know

Artist 52 [7]

First change the 0.05 to a fraction.
0.05 = 1/20
Then you have the equation:
10/20 = 0.5

5 0

2 years ago

Read 2 more answers