<span>(Y-3)^2 = 4y -12 <=> Y^2 - 6Y + 9 = 4y - 12 <=> 4y = Y^2 - 6Y + 21 <=> y = (Y^2 - 6Y + 21)/4. Solving the equation for y means that we have to express y relative to the other quantities in the equation.</span>
Answer:
A. b2 – 4ac = 0
Step-by-step explanation:
Hey user☺☺
Option a is correct
Because the graph has only one solution.
As the graph touches the x-axis at one point that means that it will have only one solution for x. But we know that a quadratic equation has two solutions. So the graph will have two equal solution and therefore the discriminant will be 0.
Hope this will help☺☺
1,700 good luck hope it helps you 100*17=1,700
