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jeka57 [31]
2 years ago
14

What is the equation in point-slope form of the line passing through (−2, 0) and (2, 8)? (1 point) y = 2(x + 2) y = 2(x − 2) y =

−2(x − 2) y = −2(x + 2)
Mathematics
1 answer:
Sonja [21]2 years ago
8 0

Answer: y=2(x+2)

Step-by-step explanation:

The slope of the line is

y=\frac{8-0}{2-(-2)}=\frac{8}{4}=2

Using the point (-2, 0) to substitute into point-slope form, we get the equation to be \boxed{y=2(x+2)}

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5 0
3 years ago
NEED HELP ASAP!!!!!!!!!!!
zhenek [66]

The equation  x=tan^{-1}(\frac{12}{5}) can be used to find the measure of ∠BAC ⇒ 2nd answer

Step-by-step explanation:

Let us revise the trigonometry ratios in the right triangle ABC, where B is the right angle, AC is the hypotenuse, AB and BC are the legs of the triangle

The trigonometry ratios of the ∠BAC, the opposite side to this angle is BC and the adjacent side to it is AB are

  • sin(BAC)=\frac{opposite}{hypotenuse}=\frac{BC}{AC}
  • cos(BAC)=\frac{adjacent}{hypotenuse}=\frac{AB}{AC}
  • tan(BAC)=\frac{opposite}{adjacent}=\frac{BC}{AB}

In Δ ABC

∵ ∠ BCA is a right angle

∴ The hypotenuse is AB

∵ The adjacent side to ∠CAB is AC

∵ The opposite side to ∠CAB is BC

∵ AB = 13 units ⇒ hypotenuse

∵ CB = 12 units ⇒ opposite

∵ AC = 5 units ⇒ adjacent

- Let us find the trigonometry ratios of angle BAC

∵ m∠CAB is x

∵ sin(x)=\frac{BC}{AB}

∴ sin(x)=\frac{12}{13}

∴ x=sin^{-1}(\frac{12}{13})

∵ cos(x)=\frac{AC}{AB}

∴ cos(x)=\frac{5}{13}

∴ x=cos^{-1}(\frac{5}{13})

∵ tan(x)=\frac{BC}{AC}

∴ tan(x)=\frac{12}{5}

∴ x=tan^{-1}(\frac{12}{5})

The equation  x=tan^{-1}(\frac{12}{5}) can be used to find the measure of ∠BAC

Learn more:

You can learn more about the trigonometry ratios in brainly.com/question/4924817

#LearnwithBrainly

4 0
3 years ago
Read 2 more answers
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