Question

3x+7-6=(8/7)-0Value of x?​

Answer 1

Answer:

$\boxed{\sf x = \dfrac{1}{21}}$

Explanation:

$\rightarrow \sf 3x+7-6= \dfrac{8}{7} - 0$

simplify the following

$\rightarrow \sf 3x+1= \dfrac{8}{7}$

subtract 1 from both sides

$\rightarrow \sf 3x+ 1 -1= \dfrac{8}{7} - 1$

simplify the following

$\rightarrow \sf 3x= \dfrac{1}{7}$

multiply both sides by 1/3

$\rightarrow \sf 3x \cdot \dfrac{1}{3}= \dfrac{1}{7}\cdot \dfrac{1}{3}$

simplify the following

$\rightarrow \sf x = \dfrac{1}{21}$

Answer 2

$3x + 7 - 6 = \frac{8}{7} - 0 \\ \\ 3x + 1 = \frac{8}{7} \\ \\ 3x = \frac{8}{7} - 1 \\ \\ 3x = \frac{ 8 - 7}{7} \\ \\ 3x = \frac{1}{7} \\ \\ x = \frac{1}{7 \times 3} \\ \\ x = \frac{1}{21} .$