F = t ⇨ df = dt
dg = sec² 2t dt ⇨ g = (1/2) tan 2t
⇔
integral of t sec² 2t dt = (1/2) t tan 2t - (1/2) integral of tan 2t dt
u = 2t ⇨ du = 2 dt
As integral of tan u = - ln (cos (u)), you get :
integral of t sec² 2t dt = (1/4) ln (cos (u)) + (1/2) t tan 2t + constant
integral of t sec² 2t dt = (1/2) t tan 2t + (1/4) ln (cos (2t)) + constant
integral of t sec² 2t dt = (1/4) (2t tan 2t + ln (cos (2t))) + constant ⇦ answer
Ask me your other questions.i hope it was helpful
Answer:
Inside the triangle - Acute Triangle
Outside the triangle - Obtuse Triangle
On the hypotenuse - Right Triangle
Step-by-step explanation:
The <u>circumcenter</u> is the point where the perpendicular bisectors of a triangle intersect.
In the special case of a right triangle, the circumcenter lies exactly at the midpoint of the hypotenuse.
The circumcenter of an acute triangle lies inside the triangle.
The circumcenter of an obtuse triangle lies outside the triangle.
Let the three odd integers be x - 2, x and x + 2
x - 2 + x = 3(x + 2) + 7
2x - 2 = 3x + 6 + 7
2x - 2 = 3x + 13
3x - 2x = -2 - 13
x = -15
The three consecutive odd integers are -17, -15 and -13.
