2 years ago

G(x) = x3 + 6x2 + 12x + 8

Mathematics

1 answer:

STatiana [176]2 years ago

8 0

The value of the function g(x) = x^3 + 6x^2 + 12x + 8 when x = -1 is 1

<h3>How to evaluate the function?</h3>

The equation of the function is given as:

g(x) = x^3 + 6x^2 + 12x + 8

When x = -1, we have:

g(-1) = (-1)^3 + 6(-1)^2 + 12(-1) + 8

Evaluate the expression

g(-1) = 1

Hence, the value of the function g(x) = x^3 + 6x^2 + 12x + 8 when x = -1 is 1

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