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SIZIF [17.4K]
3 years ago
7

CAN ANYONE HELP ME WITH THIS QUESTION...Plzz

Mathematics
2 answers:
Lelechka [254]3 years ago
5 0

Answer:

AO and OC

x+8 and 16-x

x+8 = 16-x

x+x= 16-8

2x= 8

x= 8/2

x=4

DO and OB

2y+13 and 5y+4

2y+13 = 5y+4

2y-5y= 4-13

-3y = -9

y= 9/3

y= 3

Step-by-step explanation:

i hope this helps

if this helps let me know

tino4ka555 [31]3 years ago
5 0

Answer:

Step-by-step explanation:

2y + 13 = 5y + 4 { diagonals of a rhombus bisect each other }

by transposing,

2y - 5y = 4 - 13

-3y = -9

both the minus signs get cancelled,

3y = 9

y = 9/3

y = 3

x + 8 = 16 - x  { diagonals of a rhombus bisect each other }

again by substituting,

x + x = 16 - 8

2x = 8

x = 8/2

x = 4

∴ x = 4 and y = 3

hope this helps

plz mark s brainliest!!!!!!!

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We know that,

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So, According to the question :

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{\longrightarrow \it\qquad { \ { {  38 \: }^{ \circ}   + x + x  =  180{}^{ \circ} }}}

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{\longrightarrow \it\qquad { \ { {  38 \: }^{ \circ}   + 2x   =  180{}^{ \circ} }}}

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{\longrightarrow \it\qquad { \ {   2x   =  142{}^{ \circ}  }}}

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