Answer:
0.999987
Step-by-step explanation:
Given that
The user is a legitimate one = E₁
The user is a fraudulent one = E₂
The same user originates calls from two metropolitan areas = A
Use Bay's Theorem to solve the problem
P(E₁) = 0.0131% = 0.000131
P(E₂) = 1 - P(E₁) = 0.999869
P(A/E₁) = 3% = 0.03
P(A/E₂) = 30% = 0.3
Given a randomly chosen user originates calls from two or more metropolitan, The probability that the user is fraudulent user is :
= 0.999986898 ≈ 0.999987
1. 4x - 8 + 2x + (-5x) + x^2 - 3 = 4x - 8 + 2x - 5x + x^2 - 3...now, we just combine like terms....lets group them...it will be easier ...x^2 + (4x + 2x - 5x ) - 8 - 3 = x^2 + x - 11
2. 2x + 5x = 8x
3. 2r + 4 + 3x - 2 = 3x + 2r + (4 - 2) = 3x + 2r + 2
4. 3x - 2y - x + 5y = (3x - x) + (5y - 2y) = 2x + 3y
5. 2y^2 - 8y^3 + 5y - 5y^2 + 4y^3 = (4y^3 - 8y^3) + (2y^2 - 5y^2) + 5y =
-4y^3 - 3y^2 + 5y
x^2 - 7x + 15
_________________
(x+4)/ x^3 - 3x^2 - 13x + 78
- x^3 + 4x^2
----------------
- 7x^2 - 13x
- - 7x^2 - 28x
------------------
15x + 78
- 15x + 60
-------------
18
remainder = 18
Answer: 20
Step-by-step explanation:
Hello!
The graph y < -2/3x + 2 has a dotted line. That means that any points on the dotted line or not shaded, is not a solution to this inequality. Since we are given 4 choices, we can substitute those values into the given inequality to see if it is true.
A) (0, 2)
2 < -2/3(0) + 2
2 < 2, this is false.
B) (3, 0)
0 < -2/3(3) + 2
0 < -2 + 2
0 < 0, this is false.
C) (0, 0)
0 < -2/3(0) + 2
0 < 2, this is true.
D). (0, 3)
3 < -2/3(0) + 2
3 < 2, this is false.
To check if choice C) (0, 0) is true, we should look at the given graph.
Since (0, 0) is in the shaded area, and is not graphed on the dotted line, therefore, a solution to this linear inequality is C, (0, 0).
