(t-1)(t+1) = t^2-1 through the difference of squares rule
So,
(t-1)(t+1)(t^2+1)
(t^2-1)(t^2+1)
(x-1)(x+1) ... let x = t^2
x^2-1 .... another application of the difference of squares rule
(t^2)^2 - 1... plug in x = t^2
t^4 - 1
ANSWER: 1.8 = 18/10 which is also equal to 4/5
How to convert it:
Multiply both top and bottom by 10:
1 × 10 = 10
1.8 × 10 = 18
To simply it:
18 ÷ 2 = 9
10 ÷ 2 = 5
As an improper fraction, that could also be expressed as: 4/5
I hope this helped! c:
Y - x = 9
12 = 1/3x
The first thing you want to do when solving a system of equations is isolating one of the variables.
Since the second equation only contains x, we can isolate x in the first equation.
y - x = 9
y = x + 9
x = y - 9
You can also solve the second equation without any previous solving.
12 = 1/3x
Multiple both sides by 3/1 or 3
x = 36
Now we can set them equal to each other
36 = y - 9
y = 45
Answer: x = 36 and y = 45
Answer:
36÷3÷2÷3=2
Step-by-step explanation:
Six million, seven hundred and thirty five thousand, eight hundred and thirty four
hope this helps :)