5y² + 2xy – 20x - 100
Step-by-step explanation:
Assume that the distance between City A and City B is <em>x</em> miles,
& the speed of the plane from City A to B is<em> y </em>mph;
The return trip is 20 mph slower so the plane's speed is <em>(y – 20)</em> mph
Since <em>time = distance/speed;</em> The time taken by the plane from City A to B is <em>x / y</em> hrs.
The time taken in return flight is;
<em>x / (y - 20)</em> hrs
The layover was 5hrs long. Therefore the total time taken on the who return trip journey is;
x/y + x/(y-20) + 5
multiply each individual fraction with the LCM of the denominators
x(y-20) + xy + 5 y(y-20)
xy -20x +xy + 5y² – 100
5y² + 2xy – 20x - 100
Answer:
5
Step-by-step explanation:
5
-5
|-3| = 3
-6
5 > 3 > (-5) > (-6)
Thus, 5 is the Greatest
<u>-TheUnknownScientist</u>
All we have to do to find the solution to the system of equations represented by the given graph is find the two lines' intersection point. Here, we can see that the two lines intersect at the point (3, 4). Hence, the solution to the systems of equations is (3, 4). Hope this helps!
Answer:
The translation is left 4 units
Step-by-step explanation:
we know that
Is a vertical parabola open upward with vertex at (15,3)
Is a vertical parabola open upward with vertex at (11,3)
so
The rule of the translation of (15,3) ----> (11,3) is equal to
(x,y) ----> (x-4,y)
That means ----> The translation is left 4 units
Let the rate of the current be x mph and rate of the boat in still water be y mph.
So the relative speed of the boat with the current ( downstream) = y + x and against the current (upstream) it = y - x.
Then , using speed = distance / time:-
y - x = 120/3 = 40
y + x = 120/2 = 60
Adding the 2 equations:-
2y = 100
y = 50
And substituting in the frst equation:-
50 - x = 40
x = 10
Answer:- Rate of boat in still water = 50 mph and rate of the current = 10 mph.