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Katen [24]
2 years ago
13

Are the equations 6x-6=3x and x-1=3x equivalent?​

Mathematics
1 answer:
expeople1 [14]2 years ago
4 0

Answer:

No, they aren't the same (equivalent).

Step-by-step explanation:

First, solve for both equations:

<u>Equation #1</u>:  <em>6x-6=3x </em>

Simplifying

6x + -6 = 3x

Reorder the terms:

-6 + 6x = 3x

Solving

-6 + 6x = 3x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-3x' to each side of the equation.

-6 + 6x + -3x = 3x + -3x

Combine like terms: 6x + -3x = 3x

-6 + 3x = 3x + -3x

Combine like terms: 3x + -3x = 0

-6 + 3x = 0

Add '6' to each side of the equation.

-6 + 6 + 3x = 0 + 6

Combine like terms: -6 + 6 = 0

0 + 3x = 0 + 6

3x = 0 + 6

Combine like terms: 0 + 6 = 6

3x = 6

Divide each side by '3'.

x = 2

Simplifying

<h3><em>x = 2</em></h3>

<u>Equation #2</u><em>: </em><em>x-1=3x</em>

Simplifying

x + -1 = 3x

Reorder the terms:

-1 + x = 3x

Solving

-1 + x = 3x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-3x' to each side of the equation.

-1 + x + -3x = 3x + -3x

Combine like terms: x + -3x = -2x

-1 + -2x = 3x + -3x

Combine like terms: 3x + -3x = 0

-1 + -2x = 0

Add '1' to each side of the equation.

-1 + 1 + -2x = 0 + 1

Combine like terms: -1 + 1 = 0

0 + -2x = 0 + 1

-2x = 0 + 1

Combine like terms: 0 + 1 = 1

-2x = 1

Divide each side by '-2'.

x = -0.5

Simplifying

<h3><em>x = -0.5</em></h3>
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Complete question:

The manager of a supermarket would like to determine the amount of time that customers wait in a check-out line. He randomly selects 45 customers and records the amount of time from the moment they stand in the back of a line until the moment the cashier scans their first item. He calculates the mean and standard deviation of this sample to be barx = 4.2 minutes and s = 2.0 minutes. If appropriate, find a 90% confidence interval for the true mean time (in minutes) that customers at this supermarket wait in a check-out line

Answer:

(3.699, 4.701)

Step-by-step explanation:

Given:

Sample size, n = 45

Sample mean, x' = 4.2

Standard deviation \sigma = 2.0

Required:

Find a 90% CI for true mean time

First find standard error using the formula:

S.E = \frac{\sigma}{\sqrt{n}}

= \frac{2}{\sqrt{45}}

= \frac{2}{6.7082}

SE = 0.298

Standard error = 0.298

Degrees of freedom, df = n - 1 = 45 - 1 = 44

To find t at 90% CI,df = 44:

Level of Significance α= 100% - 90% = 10% = 0.10

t_\alpha_/_2_, _d_f = t_0_._0_5_, _d_f_=_4_4 = 1.6802

Find margin of error using the formula:

M.E = S.E * t

M.E = 0.298 * 1.6802

M.E = 0.500938 ≈ 0.5009

Margin of error = 0.5009

Thus, 90% CI = sample mean ± Margin of error

Lower limit = 4.2 - 0.5009 = 3.699

Upper limit = 4.2 + 0.5009 = 4.7009 ≈ 4.701

Confidence Interval = (3.699, 4.701)

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Earnings = $1082 (to the nearest cent)

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