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Evgen [1.6K]
2 years ago
10

Find the value of x in the figure

Mathematics
1 answer:
SOVA2 [1]2 years ago
5 0

the sum of all the angles in a hexagon is 720°, so:

(4x-5)+117+(3x-3)+(3x+6)+118+(4x-3)=720

4x+3x+3x+4x= 720+5-117+3-6-118+3

14x=490

x= 490/14

x= 35

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Answer:

(-5,4)

Step-by-step explanation:

To reverse our steps we need to go up 4 units and down 3 units

+4 -3 = +1

This is in the y direction

(-5,3+1)

(-5,4)

7 0
3 years ago
The weights for newborn babies is approximately normally distributed with a mean of 6.2 pounds and a standard deviation of 2 pou
Kobotan [32]

Answer:

1.    758 newborn babies

2.   918 newborn babies

3.   756 newborn babies

4.   587 newborn babies

Step-by-step explanation:

Let's start by defining the following event :

W : ''The weight of a newborn baby''

W ~ N(μ,σ) Where N is the normal distribution, μ is the mean and σ is the standard deviation

W ~ N(6.2,2)

To calculate probability, we need to turn this variable into a N(0,1) by doing the following :

First we subtract the mean to W and then we divide by the standard deviation

[(W-μ) / σ] ~ N(0,1)

1. P(5

P(\frac{5-(6.2)}{2}

P(-0.6

Where Z ~ N(0,1)

P(-0.6 is the area below the normal curve N(0,1) between the values -0.6 and 0.9

P(-0.6<Z<0.9) = Φ(0.9) - Φ(-0.6)

Where Φ is the cumulative distribution for N(0,1)

P(-0.6<Z<0.9) = Φ(0.9) - Φ(-0.6) = 0.8159 - 0.2743 = 0.5416

Then the probability of the variable W to be between 5 and 8 pounds is 0.5416

To find the number of newborn babies expected to weigh between 5 and 8 pounds we multiply the group of 1400 and the probability

(1400).(0.5416)=758.24

758.24 ≅ 758

Then 758 newborn babies are expected to weigh between 5 and 8 pounds

2.

P(W

P(Z<0.4) = Φ(0.4) = 0.6554

The expected number of newborn babies is

(1400).(0.6554)=917.56

917.56 ≅ 918

918 newborn babies are expected to weigh less than 7 pounds

3.

P(W>6)=1-P(W

1-P(Z<-0.1) = 1 - Φ(-0.1) = 1 - 0.4602 = 0.5398

The expected number of babies is

(1400).(0.5398)=755.72

755.72 ≅ 756

The expected number of babies to weigh more than 6 pounds is 756

4.

P(6.2

P(0<Z<1.4) = Φ(1.4) - Φ(0) = 0.9192 - 0.500 = 0.4192

The expected number of babies is

(1400).(0.4192)= 586.88

586.88 ≅ 587

587 newborn babies are expected to weigh between 6.2 and 9 pounds

8 0
3 years ago
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Answer:

find 16.5% of 650 by turning 16.5 into a decimal.

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Answer:

Step-by-step explanation:

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Slope-intercept equation for line of slope ⅓ and y-intercept 1:

y = ⅓x+1

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