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2 years ago

A bag of paper clips contains:

Mathematics

2 answers:

oee [108]2 years ago

8 0

14 times
Step-by-step explanation: add all colors
up for total which is 25
since 7 out of the 25 total paper clips are
yellow you would have a 7/25 chance of
getting yellow after 1 pick.
since you pick and replace 50 times do
(7/25) × 50 which gives you 14 times
yellow will be drawn.

Zina [86]2 years ago

7 0

Answer:

14 times

Step-by-step explanation: add all colors up for total which is 25

since 7 out of the 25 total paper clips are yellow you would have a 7/25 chance of getting yellow after 1 pick.

since you pick and replace 50 times do (7/25) X 50 which gives you 14 times yellow will be drawn.

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Tara has two standard, six-sided dice. If she rolls them 36 times, how many times should she expect a sum less than 5 to show up

andreyandreev [35.5K]

There are six sides on each die. For each possible score on Die 1, there are six possible scores on Die 2. So the number of possible combinations is 6*6 = 36.
It follows that if the dice are thrown 36 times, you would expect each combination to come up once. 

We therefore simply need to know how many combinations add up to less than 5. (I've interpreted this as not including a total of 5 itself). 
These combinations are: 1 and 1, 2 and 1, 1 and 2, 2 and 2, 3 and 1, and 1 and 3 ---> six combinations out of 36. 

So you'd expect a sum less than 5 six times.

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3 years ago

Which is larger 1:40 or 1:60

agasfer [191]

1:40.

1:40 is equal to 1/40, while 1:60 is equal to 1/60.

1/40 is the bigger fraction, so 1:40 is the correct answer.

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4 years ago

What fraction of 56 of 21?

Paraphin [41]

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3 years ago

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ser-zykov [4K]

Answer:

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3 years ago

Jane is 5 times older than her sister. In 3 years, Jane’s sister will be 1/4 her age. Find the ages now

Korolek [52]

The present age of Jane is 45 years old and present age of her sister is 9 years old

Solution:

Let the present age of Jane be "x"

Let the present age of her sister be "y"

Jane is 5 times older than her sister

present age of Jane = 5(present age of her sister)

x = 5y ---------- eqn 1

In 3 years, Jane’s sister will be 1/4 her age

Age of sister after 3 years = 3 + y

Age of jane after 3 years = 3 + x

Age of sister after 3 years = 1/4(age of jane after 3 years)

$3 + y = \frac{1}{4}(3 + x)$

Substitute eqn 1 in above equation

$3 + y = \frac{1}{4}(3 + 5y)\\\\12 + 4y = 3 + 5y\\\\5y - 4y = 12 - 3\\\\y = 9$

Substitute y = 9 in eqn 1

x = 5(9)

x = 45

Thus present age of Jane is 45 years old and present age of her sister is 9 years old

3 0

4 years ago